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Mariulka [41]
3 years ago
8

Use lagrange multipliers to find the maximum volume of a rectangular box that is inscribed in a sphere of radius r

Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0

For the derivative tests method, assume that the sphere is centered at the origin, and consider the circular projection of the sphere onto the xy-plane. An inscribed rectangular box is uniquely determined

1

by the xy-coordinate of its corner in the first octant, so we can compute the z coordinate of this corner by

x2+y2+z2=r2 =⇒z= r2−(x2+y2). Then the volume of a box with this coordinate for the corner is given by

V = (2x)(2y)(2z) = 8xy r2 − (x2 + y2),

and we need only maximize this on the domain x2 + y2 ≤ r2. Notice that the volume is zero on the boundary of this domain, so we need only consider critical points contained inside the domain in order to carry this optimization out.

For the method of Lagrange multipliers, we optimize V(x,y,z) = 8xyz subject to the constraint x2 + y2 + z2 = r2<span>. </span>

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DO NOT LISTEN TO THE OTHER PERSON, you can CLEARLY see thats not the right answer. She/He is bluffing.

The true answer:
The shape has 4 faces. Faces means the sides of a 3d figure/the sides are the 2d shapes that form together to form one 3d figure. Btw that figure is a triangular pyramid.
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cestrela7 [59]

Answer:

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Step-by-step explanation:

( - 5 - 7 {x}^{2} ) + (5 + 7 {x}^{3} ) \\  =  - 5 - 7 {x}^{2}  + 5 + 7 {x}^{3}  \\  = - 7 {x}^{2}  + 7 {x}^{3}

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Step-by-step explanation: In order to decide whether the given fractions are equivalent, first write each fraction in lowest terms. Remember, a fraction is written in lowest terms if the greatest common factor of the numerator and the denominator is 1.

For our first fraction which is 3/4, the greatest common factor of 3 and 4 is 1, the fraction is already in lowest terms.

For our second fraction however, since the greatest common factor of 6 and 8 is 2, we must divide both the numerator and denominator by 2 which gives us 3/4.

3/4 = 3/4 which means these fractions are equivalent.

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