Answer:
The answer to your question is Triangle's area = 520 in², Square's area = 576 in²
Step-by-step explanation:
Process
1.- Calculate the area of the triangle
-Find the length of the base using the Pythagorean theorem
c² = a² + b²
-Solve for b²
b² = c² - a²
-Substitution
b² = 37² - 35²
-Simplification
b² = 1369 - 1225
b² = 144
b = 12 in
-Find the base
base = 2(12) = 24 in
-Find the area of the triangle
Area = base x height / 2
-Substitution
Area = 24 x 35 / 2
-Simplification
Area = 420 in²
2.- Find the area of the square
Area = side x side
-Substitution
Area = 24 x 24
-Result
Area = 576 in²
Answer:
80
Step-by-step explanation:
If we assume the triangles are similar and are isosceles, and that BK is an altitude, then we can work the problem.
Triangle OKN will be similar to triangle BKA, so ...
AN : AK = BO : BK = 1 : 3
Then ...
AN : AK : KC = 1 : 3 : 3
In terms of ratio units, ...
AN = 1
AC = 3+3 = 6
NC = 6-1 = 5
This means NC : AC = 5 : 6. The triangle perimeters will have the same ratio.
perimeter(NMC) = 5/6·perimeter(ABC) = 5/6·96
perimeter(NMC) = 80
I don’t appreciate you being there for a long week and I’m not good enough for it and you don’t feel good enough for
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
Answer:
f) 5x 3
Step-by-step explanation:
You do multiplication first
