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artcher [175]
2 years ago
15

If you can solve this, your a genius.. 900 + 1 = ?

Mathematics
2 answers:
noname [10]2 years ago
8 0

Answer:

901

Step-by-step explanation:

900 + 1 = 901

Marizza181 [45]2 years ago
7 0

Answer:i think i know.. 901

Step-by-step explanation: 900 + 1 = 901

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Explain why 1 hundred 4 tens and 14 tens name the same amount.
artcher [175]
Because 14 tens is 10+4 tens
10 tens is a hundred
so 14 tens is a hundred + 4 tens
7 0
3 years ago
Please help me and I will make you the brainiest
wlad13 [49]

Answer:

y=a-4 divided 3-a and a cut so remember 4divided3  so, y= 1.33

Step-by-step explanation:

7 0
3 years ago
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
Verify that -tan2x = (2tanx) / (sec^2x - 2)
sashaice [31]

Answer:

Below.

Step-by-step explanation:

- tan 2x =   -2tanx / (1 - tan^2x)

Using the identity  tan^2x = sec^2x - 1 and substituting for tan^2x:

- tan 2x = -2 tanx / (1 - (sec^2x - 1))

=   2 tanx / ( - 1(sec^2x + 2))

= 2 tan x / (sec^2 x - 2)

8 0
3 years ago
Why do we need to find the average of something
daser333 [38]

Answer:

To know what is the average of it

Step-by-step explanation:

7 0
3 years ago
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