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3 years ago

Round 14,456 to nearest ten

Mathematics

1 answer:

V125BC [204]3 years ago

7 0

Answer:

14,460.

Step-by-step explanation:

14,456 up by 4. anything 6 or above goes up. the tenth place is the second to last number.

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Answer:

1. 11

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3 years ago

Ava and her little sister, April, both have the same birthdays on the same day. Ava is 12 years old, April is nine years old. Di

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Answer:

6 years ago

Step-by-step explanation:

12 - 6 = 6

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4 years ago

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5.5.35 Write the equation in standard form using integers. y= -3/7x - 7 The equation in standard form is

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Answer:

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3 years ago

Find the equation of the parallel to the line 3x-2y=5 and passing through the midpoint of the line segment joining the points (-

levacccp [35]

Given:

The equation of parallel line is:

$3x-2y=5$

The required line passing through the midpoint of the line segment joining the points (-4,2) and (2,4).

To find:

The equation of required line.

Solution:

Midpoint of line segment joining the points (-4,2) and (2,4) is:

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Midpoint=\left(\dfrac{-4+2}{2},\dfrac{2+4}{2}\right)$

$Midpoint=\left(\dfrac{-2}{2},\dfrac{6}{2}\right)$

$Midpoint=\left(-1,3\right)$

It means the required line passes through the point (-1,3).

The slope of line $Ax+By=C$ is:

$m=\dfrac{-A}{B}$

The given equation is:

$3x-2y=5$

Here, A=3 and B=-2. So, the slope of the line is:

$m=\dfrac{-3}{-2}$

$m=1.5$

Slope of parallel lines are same. So, the slope of the required line is 1.5.

The required line passes through the point (-1,3) with slope 1.5. So, the equation of the line is:

$y-y_1=m(x-x_1)$

$y-3=1.5(x-(-1))$

$y-3=1.5(x+1)$

$y-3=1.5x+1.5$

Adding 3 on both sides, we get

$y=1.5x+1.5+3$

$y=1.5x+4.5$

Therefore, the equation of the required line is $y=1.5x+4.5$ .

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3 years ago

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