Your answer is 3:05.
You must add on to 9:40. So what I did was 9 + 5 = 14.
14 - 12 = 2.
So far it's 2:40.
25 minutes + 40. = 65.
Well there are 60 minutes in an hours. So 65 would be equal to 1H and 5min.
Now take that 1 hour. Add it to 2.
3 hours. And take your 5 minutes.
There! 3:05
Vertical angles are congruent...they are equal....so set them equal to each other and solve for x
6x - 22 = 4x + 2
6x - 4x = 2 + 22
2x = 24
x = 24/2
x = 12 <==
This revolves around exact trig values - no easy way to say this, you just need to memorise them. They are there for sin cos and tan, but I will give you the main tan ones below - note this is RADIANS (always work in them when you can, everything is better):
tan0: 0
tanpi/6: 1/sqrt(3)
tanpi/4: 1
tanpi/3: sqrt(3)
tanpi/2: undefined
Now we just need to equate -2pi/3 to something we understand. 2pi/3 is 1/3 of the way round a circle, so -2pi/3 is 1/3 of the way round the circle going backwards (anticlockwise), so on a diagram we already know it's in the third quadrant of the circle (somewhere between pi and 3pi/2 rads).
We also know it is pi/3 away from pi, so we are looking at sqrt(3) or -sqrt(3) because of those exact values.
Now we just need to work out if it's positive or negative. You can look up a graph of tan and it'll show that the graph intercepts y at (0,0) and has a period of pi rads. Therefore between pi and 3pi/2 rads, the values of tan are positive. Therefore, this gives us our answer of sqrt(3).
In 1 minute, bison runs 3520 feet
In 60 minutes, the bison would run
3520*60 feet
211200 feet per hour.
These are equivalent to;
40 miles per hour since 1 mile is equivalent to 5280 feet.
The bison is faster by 10 miles per hour
Answer:

Step-by-step explanation:
In this exercise, we have two equations, namely:

And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:

Then:

So here we have two lines.
The first one is:

This line passes through the origin and has a slope 
The second one is:

This line has a slope
and cuts the y-axis at 
By using graph tools, we get the graph shown below, then:
