Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N()' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N()' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.
Formula for probability of an event E can be observed as:
So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Isolate the variable by dividing each side by factors that don't contain the variable.
x = 1
-6+3x+4=2-4x+3
-8+7x+1=0
7x=7
x=1
Answer:0.75 milligrams will be present in 24 hours
Step-by-step explanation:
Step 1
The formula for radioactive decay can be written as
N(t)=No (1/2)^(t/t 1/2)
where
No= The amount of the radioactive substance at time=0=milligrams
t 1/2= the half-life= 6 hours
t=24 hours
N(t) = the amount at time t
Step 2--- Solving
N(t)=No (1/2)^(t/t 1/2)
=N(t)=12 x ( 1/2) ^ (24/6)
= 12 x (1/2) ^4
= 12 x 0.0625
= 0.75 milligrams
Answer:
12.57555 rounded to 12.5756
Step-by-step explanation:
34'=34*1/60=0.56°
56''=56/1/3600=0.01555°
12°+0.56°+0.01555°=12.57555°
Answer:
4x^2 -5x -2
Step-by-step explanation:
= 5x^2 -3x -7 -x^2 -2x +5
= (5 -1)x^2 +(-3 -2)x +(-7 +5)
= 4x^2 -5x -2