Answer:
a) N = 2^8 = 256
b)N = 2^8 + 2^7 +2^6 +2^5 +2^4 +2^3 +2^2 +2^1
Step-by-step explanation:
Given;
String of length 8, with two options (0 or 1) each.
a) for the number of bits of strings of length 8.
Each digit of the 8 digit string has 2 options.
For 8 digit, we have
N = 2×2×2.... = 2^8 =256
b) for bit of strings of length 8 or less.
For n string = 2^n
For n < 8
The number of bit strings for length 8 or less are;
N = N8 +N7 + N6 + ... +N1
N = 2^8 + 2^7 +2^6 +2^5 +2^4 +2^3 +2^2 +2^1
I’m not sure completely if I’m being honest but I get points
28/8 = (28÷4)/(8÷4) = 7/2;
m^2 / m^3 = (m^2÷m^2)/(m^3÷m^2) = 1/m;
n^4/n^2 = (n^4÷n^2)/(n^2÷n^2) = n^2;
Finally, we obtain 7n^2/2m ;
Answer:
roots=(5±sqrt(33))/4
Step-by-step explanation:
roots=(-b±sqrt(b^2-4ac))/2a
roots=(-(-5)±sqrt(25+8))/(2*2)
roots=(5±sqrt(33))/4
roots=(5+sqrt(33))/4 and (5-sqrt(33))/4
594.15
Step-by-step explanation:
