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3 years ago

2 1/5 + 1 3/5 = ??? Plz help

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

5 0

Answer:

$3 \frac{4}{5}$

Step-by-step explanation:

1) Add the whole numbers first.

$3 + \frac{1}{5} + \frac{3}{5}$

2) Join the denominators.

$3 + \frac{1 + 3}{5}$

3) Simplify.

$3 \frac{4}{5}$

hence, the answer is 3 4/5.

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Given

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Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

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