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3 years ago

Can someone help me find the perimeter please

Mathematics

1 answer:

vichka [17]3 years ago

6 0

Ans is 392 mm and approx 400mm as perimeter of semi circle is pi r which is 22/7*16 + 40 mm which is the total of the two side of the triangle given.
I hope this will help you

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-2/4 times 344/9=? Please help me . I dont really understand this question.

baherus [9]

Answer:

-19 1/9

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The temperature in Celsius would be,

elena-14-01-66 [18.8K]

First derisive the equation for C

$\\ \sf\longmapsto F=\dfrac{9}{5}C+32$

$\\ \sf\longmapsto C+32=\dfrac{5}{9}F$

$\\ \sf\longmapsto C=\dfrac{5}{9}F-32$

F=101F

$\\ \sf\longmapsto C=\dfrac{5}{9}101-32$

$\\ \sf\longmapsto C=\dfrac{505}{9}-32$

$\\ \sf\longmapsto C=56.1-32$

$\\ \sf\longmapsto C=24.1°C$

8 0

3 years ago

Please help, I need help. I don't understand.

Lana71 [14]

Find slope of both

(11,2)
(22,4)

$\\ \tt\hookrightarrow m=\dfrac{4-2}{22-11}=\dfrac{2}{11}=1.8$

(0,0)
(5,1)

$\\ \tt\hookrightarrow m=\dfrac{1-0}{5-0}=\dfrac{1}{5}=0.2$

Option C is correct

7 0

2 years ago

The ratio of boys and girls in a 4:3.If there are 20 boys, find the number of girls.

Elina [12.6K]

Answer:

There are 15 girls.

Step-by-step explanation:

The ratio is 4:3, meaning there are 7 parts.

4 parts= 20 (Boys)

This means 1 part is 20 divided by 4.

1 part= 5

3 parts= Amount of girls.

3 x 5 = 15.

There are 15 girls.

6 0

2 years ago

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In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.

Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

Solution:

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

$\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}$

where c is the proportionality constant

$\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}$

Hence, x value is 12 when y value is 9

3 0

3 years ago