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3 years ago

Devon answered 23 out of 25 problems on a math test correctly.what percent of the problems did devon answer corectly?

Mathematics

1 answer:

vova2212 [387]3 years ago

6 0

Answer:

92%

Step-by-step explanation:

(23/25)×100%

23×4

92%

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SOMEONE PLS HELP<br> the multiplicative inverse of 1/5 and (2x-1/5)

tigry1 [53]

Answer:

You multiply 5 by 1/5 to get 1. So with 2x, you multiply by 1/(2x) to get 1. That's about all you know, since we only know that x is positive.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

5. -[-2(x-4) - |1-3|] = -2x18

irina [24]

Solving the expression $-[-2(x-4) - |1-3|] = -2x18$ we get value of x: $x=\frac{3}{19}$

Step-by-step explanation:

We need to solve the equation $-[-2(x-4) - |1-3|] = -2x18$ and find value of x

Solving:

$-[-2(x-4) - |1-3|] = -2x18$

Multiply -2 with terms inside the bracket

$-[-2x+8 - |1-3|] = -2x18$

Solving |1-3| we get |-2|=2

$-[-2x+8 - 2] = -2x18$

$-[-2x+6] = -2x18$

Multiply (-) sign with terms inside the bracket

$+2x-6 = -2x18$

Multiply 2x with 18

$2x-6 = -36x$

Add 36x on both sdides

$2x-6+36x =0$

$38x-6 =0$

Add 6 on both sides:

$38x =6$

Divide both sides by 38

$x=\frac{6}{38}$

Simplifying:

$x=\frac{3}{19}$

So, Solving the expression $-[-2(x-4) - |1-3|] = -2x18$ we get value of x: $x=\frac{3}{19}$

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

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4 years ago

Solve 2sin(2x) - 2sinx +2sqrt3 cosx - sqrt3 = 0

SashulF [63]

Answer:

2sin(2x)-2sinx+2sqrt3cosx-sqrt3 = 0

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4sin(x)cos(x) - 2sin(x) + 2sqrt(3)cos(x) - sqrt(3) = 0

-----

Factor:

2sin(x)[2cos(x)-1] + sqrt(3)[2cos(x)-1] = 0

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[2cos(x)-1][2sin(x)+sqrt(3)] = 0

Solve:

2cos(x)-1 = 0 or 2sin(x)+sqrt(3) = 0

cos(x) = 1/2 or sin(x) = -sqrt(3)/2

x = +/-pi/3 or x = -pi/3 or (4/3)pi

hope this helps!

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3 years ago

Read 2 more answers

Solve pls brainliest

andre [41]

Answer:

Step-by-step explanation:

1. no-has decimal

2. yes, simplifies to -2

3. yes

4. yes

5. no-2.1

8 0

3 years ago

Simplify.<br> 4/x^2-35 - 1/x+5

Oksana_A [137]

If I understand your question well, I suppose you mean $\frac{4}{ x^{2} -35} - \frac{1}{x+5}$
$\frac{4}{ x^{2} -35} - \frac{1}{x+5} = \frac{4}{(x+5)(x-7)}- \frac{1}{x+5} \\ = \frac{1}{x+5}( \frac{4}{x-7}-1) \\ = \frac{1}{x+5}( \frac{4}{x-7}- \frac{x-7}{x-7}) \\ = \frac{1}{x+5}( \frac{4-x+7}{x-7}) \\ = \frac{1}{x+5}( \frac{11-x}{x-7}) \\ = \frac{11-x}{ x^{2} -35}$

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4 years ago