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3 years ago

Consider the function f(x) = x2 + 2x – 35. If one of the zeros of the

Mathematics

1 answer:

Whitepunk [10]3 years ago

8 0

If one zeros is x= -7 then the other zero is x=5

Step-by-step explanation:

We are given the function: $f(x) = x^2 + 2x-35$

If one zeros of the function is x=-7 we need to find other zero of the function.

We can find zeros of the quadratic equation by factorizing the equation

$f(x) = x^2 + 2x-35$

Factorizing the quadratic equation:

$x^2 + 2x-35=0\\x^2-5x+7x-35=0\\x(x-5)+7(x-5)=0\\(x+7)(x-5)=0\\x+7=0\,\,and\,\,x-5=0\\x=-7\,\,and\,\,x=5$

So, if one zeros is x= -7 then the other zero is x=5

Keywords: Solving Quadratic Equation

Learn more about Solving Quadratic Equation at:

#learnwithBrainly

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3 years ago

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2 years ago

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

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Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

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Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$