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3 years ago

What are the next three terms in sequence -6,5,16,27,

1 answer:

4 0

-6 + 11 = 5
5 + 11 = 16
16 + 11 = 27

Similarly,
27 + 11 = 38
38 + 11 = 49
49 + 11 = 60

So the next 3 terms are 38,49,60

Hope This Helps You!

You might be interested in

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago

Use the graph to find the x-intercept for the equation y + 2 = 2(x + 3).

Assoli18 [71]

Answer:

The x-intercept is 2

Step-by-step explanation:

So what you would do is you would distribute the 2 to x and 3 to get the equation y+2=2x+6. Then you would subtract 2 from both sides and get y=2x+4. And because your m is your x-intercept you get the answer: 2.

3 0

3 years ago

suppose x and y vary inversely and y=10 when x=4. write a function that models the variation then find y when x =90

ankoles [38]

X = k/y
4 = k/10
k = 4 x 10 = 40
Thus, x = 40 / y

90 = 40 / y
y = 40/90 = 4/9

4 0

3 years ago

Which of the following represents the series ?

aleksklad [387]

The denominator in each term of the series is a square number, but neither $n-6$ nor $n^2+1$ are squares. So none of (1), (2), and (4) can be correct. The answer must be (3).

5 0

3 years ago

Please explain thanks

Gre4nikov [31]

<h3>Answer:</h3>

$\large\boxed{\pink{\sf \leadsto Value \ of \ LM \ is \ 11 \ units . }}$

<h3>Step-by-step explanation:</h3>

A figure is given to us in which we can see two triangles one is ∆ MPL and other is ∆MPN .

Figure :- 

$\setlength{\unitlength}{1 cm}\begin{picture}(12,12)\linethickness{0.25mm}\put(0,0){\line(1,2){2}} \put(0.001,0){\line(1,0){4}}\put(2,0){\vector(0,1){5}}\put(4,0){\line( - 1,2){2}}\put(0,-0.4){$\bf L $}\put(2,-0.4){$\bf P$}\put(4,-0.4){$\bf N $}\put(2.2,4){$\bf M $}\put(2.8, - .4){$\bf 5 $}\put(1, - .4){$\bf 5 $}\put(3.4, 2){$\bf 11 $}\put(2.3,0){\line(0,1){.3}}\put(2.3,.3){\line( - 1,0){.3}}\end{picture}$

$\underline{\blue{\sf In\: \triangle MPL \ \& \ \triangle MPN :- }}$

$\qquad \bullet LP = PN = 5 \:\:(given) \\\\\qquad \bullet MP = MP \:\:(Common) \\\\\qquad \bullet \angle MPN = \angle MPL = 90^{\circ} \:\: (given)$

Hence by SAS congruence condition ,

$\orange{\bf \triangle MPL \cong \triangle MPN }$

Hence by cpct ( Corresponding parts of congruent triangles ) we can say that , LM = NM = 11 units .

<h3>Hence the value of LM is 11 units .</h3>

4 0

2 years ago