Which of the following represents the series ?
1 answer:
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Answer:
Plese read the complete procedure below:
Step-by-step explanation:
The polynomial is p(a) = (a^4 - 6a^3 + 3a^2 + 26a – 24)
a)
1 -6 3 26 -24 |<u> 1 </u>
<u> 1 -5 -2 24</u>
1 -5 -2 24 0
The remainder is zero, then (a-1) is a factor of the polynomial
b)
1 -6 3 26 -24 |<u> 2 </u>
<u> 2 -8 10 72</u>
1 -4 5 36 48
When p(a) is divided by (a-2) the remainder 28/p(a)
1 -6 3 26 -24 |<u> - 4 </u>
<u> -4 40 172 -792</u>
1 -10 43 198 -816
When p(a) is divided by (a-2) the remainder -816/p(a)
c) I attached an image of the long division below:
The fact that the coefficients are pairwise identical (except for sign) tells you that x^2 -1 is a factor (and x-5 is the other factor). Of course, you recognize x^2-1 as a special form (the difference of squares) that is factored as (x +1)(x -1).
The zeros are x = -1, +1, +5.
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A graphing calculator confirms this.
The zeros are x = -1, +1, +5.
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A graphing calculator confirms this.