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2 years ago

Which of the following represents the series ?

Mathematics

1 answer:

aleksklad [387]2 years ago

5 0

The denominator in each term of the series is a square number, but neither $n-6$ nor $n^2+1$ are squares. So none of (1), (2), and (4) can be correct. The answer must be (3).

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15 POINT QUESTION; I REALLY NEED HELP

Ksenya-84 [330]

Answer:

the line modeling the baking powder and the flour used

Step-by-step explanation:

plato master test

7 0

2 years ago

Read 2 more answers

Look at the following graph of the given equation. Determine whether the equation is a function. Explain why or why not.

Vadim26 [7]

The equation $y=2x+2$ is a function

Explanation:

Given that the graph contains the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$

We need to determine whether the equation $y=2x+2$ is a function.

To determine the equation is a function, let us substitute the coordinates in the equation and check whether it satisfies the equation.

Let us substitute the coordinate $(-1,0)$ in the equation $y=2x+2$

Thus, we have,

$0=2(-1)+2$

$0=-2+2$

$0=0$

Thus, the coordinate $(-1,0)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(0,2)$ in the equation, we have,

$2=2(0)+2$

$2=2$

Thus, the coordinate $(0,2)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(1,4)$ in the equation $y=2x+2$

$4=2(1)+2$

$4=4$

Thus, the coordinate $(1,4)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(2,6)$ in the equation, we get,

$6=2(2)+2$

$6=6$

Thus, the coordinate $(2,6)$ satisfies the equation $y=2x+2$

Hence, the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$ satisfies the equation $y=2x+2$

Thus, the equation $y=2x+2$ is a function.

6 0

3 years ago

QUICK !! What is the image point of (2,-7) after a translation right 4 units and up 3 units ?

Paul [167]

Answer:

(6, - 4)

Step-by-step explanation:

A translation of 4 units right is equivalent to adding 4 to the x- coordinate

A translation of 3 units up is equivalent to adding 3 to the y- coordinate

(x, y) → (x + 4, y + 3) ← translation rule

Hence

(2, - 7) → (2 + 4, - 7 + 3) → (6, - 4)

6 0

3 years ago

Read 2 more answers

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an

solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?

Solution:

The random variable X can be defined as the pregnancy length in days.

Then, from the provided information $X\sim N(\mu=268, \sigma^{2}=12^{2})$ .

(a)

The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ z = 1.23

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283$

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ z = -1.645

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248$

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.

8 0

2 years ago

What are prime factors of 100

Reil [10]

2x2x5x5 or 2^2*5^5 hope this helps!

6 0

2 years ago