Tbh i depends on what kind of person you are. If you really like video games then go ahead but i guess what you are asking is how and that really doesnt answr your question but
1) YOU HAVE TO BE FULLY COMMITTED/ MOTIVATED TO THE GAME
that is the number 1 step.Also try to do a little research on the game and the systems, watch videos on how to take the system apart and back together.
I HAVE FAITH IN YOU!!! YOU CAN DO IT!!! TAKE CHARGE
Answer:
# Code in Python
dictionary={'A':1,'B':2,'C':3,'D':4}
other_dictionary={}
for keys in dictionary:
if dictionary[keys]&1==1:
temp=dictionary[keys]*dictionary[keys]-10*10
other_dictionary[keys]=temp
else:
other_dictionary[keys]=dictionary[keys]
print(other_dictionary)
assert other_dictionary
Explanation:
- Initialize a sample example dictionary and other_dictionary.
- Do a binary comparision for checking odd number
.
- Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
- For even: store the original value (from dictionary).
Wrong, You should get renters insurance to insure your items that you do have or will recieve in the future are safe
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
Answer:
Following are the description to the given points:
Explanation:
To resolve basic design restrictions, EBNF has also been developed.This principle was its lack of support can identify repeatings easily. It implies that popular BNF models, like the description of a sequence of replicable elements, are complicated and rely on contra intuitive logical math.
To set a list of words divided by commas (e.g. john, coffee, logic) for instance, we would like to say something like "a list is a word accompanied by a few commas or terms." Through EBNF, they may say so. However, there have been no "many" alternatives in the standard BNF format. So, to describe something such as "a list is a term or a number accompanied by a pair with notation and script," you have to say the same thing. Which functions, although it is difficult, as it specifies a variety of lists instead of a specific list.
Essentially, "john, coffee, logic is John's list, accompanied by coffees or, and logic" would be the earlier link. That's why in Option (a):
The return statement in Java is:
return ('”‘ (~[“] | ” [”e‘])*);
In option (c), it is the valid statement.