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Svetach [21]
3 years ago
11

What’s the value of u , help please

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Step-by-step explanation:

u-42+u-43+u-44=180

3u -129 = 180

3u = 309

u = 103

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Bob orders 2 tons of dog food every month, the order must be placed in 50 pound sacks. Each sack costs $11.99. How many 50 pound
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Answer:

80 sacks for $959.2

Step-by-step explanation:

2 tons = 4000 lbs.

If each sack cost $11.99, and is weighted at 50 pounds than

4000/50 = 80

80 x $11.99 = $959.2

4 0
3 years ago
A combination lock requires three numbers from 1 to 25. how many combinations are possible? did you use the sum rule or the prod
maria [59]
Combinations possible = 25 * 25 * 25. Product rule

The point is that numbers can be reused. 1 5 1 is a valid combination as is   4 4 4 

20 * 5 * 1 is a valid combination as is 1 25 5

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7 0
3 years ago
Joseph removes 5/8 gallon of white paint from a can.
tatiyna

Create the expression from the data:

The gallon of paint begins as a whole: 8/8

Then he removes 5/8 gallons of paint from the can: - 5/8

Then he adds 5/8 of a different colored paint to the can: + 5/8

Now combine:

8 / 8 - 5 / 8 + 5 / 8 = 8/8

The paint can is full, then he removes an amount from the can. He then pours more paint into the can that is equal to the amount he originally removed. Therefore, the paint can remained full.

7 0
3 years ago
.A retailer sold two articles at same price. He sold the first one at 10% profit and the
IRISSAK [1]

Step-by-step explanation:

so let's assume they both sold for 100 each the first article sold for 10% laws there by cost of article is 111.11 rounded the second article made 25% profit so cost must be 80 total cost is 8.89 or 5% profit I'm so sorry if im wrong

3 0
3 years ago
An algorithm takes 0.5 seconds to run on an input of size 100. How long will it take to run on an input of size 1000 if the algo
dexar [7]

Answer:

linear: 5s

quadratic: 50s

log-linear: 0.75 s

cubic: 500s

Step-by-step explanation:

Let t_1,t_2 be the running time associated with the input of sizes s_1,s_2

If the running time is linear

t_2 = t_1\frac{s_2}{s_1} = 0.5*\frac{1000}{100} = 0.5*10 = 5s

If the running time is quadratic

t_2 = t_1\left(\frac{s_2}{s_1}\right)^2 = 0.5*\left(\frac{1000}{100}\right)^2 = 0.5*10^2 = 50s

If the running time is log-linear

t_2 = t_1\frac{log(s_2)}{log(s_1)} = 0.5*\frac{log(1000)}{log(100)} = 0.5*1.5 = 0.75s

If the running time is cubic:

t_2 = t_1\left(\frac{s_2}{s_1}\right)^3 = 0.5*\left(\frac{1000}{100}\right)^3 = 0.5*10^3 = 500s

6 0
3 years ago
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