Answer:
Step-by-step explanation:
![-4x^2+11x-6=-(4x^2-11x+6)=-(4x^2-8x-3x+6)\\\\=-\left[4x(x-2)-3(x-2)]=-(x-2)(4x-3)=(-4x+3)(x-2)](https://tex.z-dn.net/?f=-4x%5E2%2B11x-6%3D-%284x%5E2-11x%2B6%29%3D-%284x%5E2-8x-3x%2B6%29%5C%5C%5C%5C%3D-%5Cleft%5B4x%28x-2%29-3%28x-2%29%5D%3D-%28x-2%29%284x-3%29%3D%28-4x%2B3%29%28x-2%29)
Q1
I like to use the standard form to write the equation of a perpendicular line, especially when the original equation is in that form. The perpendicular line will have the x- and y-coefficients swapped and one negated (remember this for Question 3). Thus, it will be
... 5x - 2y = 5(6) - 2(16) = -2
Solving for y (to get slope-intercept form), we find
... y = (5/2)x + 1 . . . . . matches selection C
Q2
The given equation has slope -3/6 = -1/2, so that will be the slope of the parallel line. (matches selection A)
Q3
See Q1 for an explanation. The appropriate choice is ...
... B. 4x - 3y = 5
Q4
The given line has slope -2, so you can eliminate all choices except ...
... D. -2x
Q5
The two lines have the same slope (3), but different intercepts, so they are ...
... A. parallel
Answer:
The scale factor is greater than 1
Step-by-step explanation:
Answer:
Y = X - 2 would be the answer.
