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Citrus2011 [14]
3 years ago
13

Evaluate the expression 3.4 ÷ 12a ÷ 4 for a = 10

Mathematics
2 answers:
Liula [17]3 years ago
6 0

Answer

its 33.4 with the plus sign instead of the divide

Step-by-step explanation:

I hoped this helped :)

Verdich [7]3 years ago
6 0

Answer:

.708333333333

Step-by-step explanation:

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What is the equation of the following line? Be sure to scroll down first to see all answer options.
Harrizon [31]
<h3><u>Answer:</u></h3>

Hence, the equation of line is:

y= -6x

<h3><u>Step-by-step explanation:</u></h3>

Clearly from the graph we could see that the line passes through the point (0,0) and (-1/2,3).

Also we know that the equation of a line passing through (a,b) and (c,d) is given as:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Here we have:

(a,b)=(0,0) and (c,d)=(-1/2,3)

Hence, the equation of line is:

y-0=\dfrac{3-0}{-\dfrac{1}{2}-0}\times (x-0)\\\\\\\\y=\dfrac{3}{\dfrac{-1}{2}}\times x\\\\y=3\times (-2)\times x\\\\y=-6x

Hence, the equation of line is:

y= -6x

6 0
3 years ago
Read 2 more answers
Turning off the water while brushing your Teeth saves 350 centilliters of water. How many liters of water can you save if you tu
Blababa [14]

Answer:

1.1l

Step-by-step explanation:

350×3=1050cl

=1.05l

rounded to nearest hundredth=1.1l

3 0
3 years ago
A cat had a litter of 5 kittens. If each sex is equally likely, what is the probability that 3 or less were female kittens?
ASHA 777 [7]

Answer:

0.8125

Step-by-step explanation:

In this question, we are tasked with calculating the probability that 3 or less of her kittens were female.

Since each bsex is of likely probability, the probability of a male kitten = probability of a female kitten = 0.5

Now to calculate for 3 or less female kitten we are calcualting P(f) ≤ 3

In each case, we use the Bernoulli approximation

P(f) ≤ 3 = 5C3 m^{2} f^{3} + 5C2 m^{2}  f^{3} + 5C1 m^{4}  f + 5C0 m^{5}  f^{0}

Where m is the probability of a male kitten and f is the probability of having a female kitten with both values = 0.5

P(f) ≤ 3 =(0.3125) + (0.3125) + (0.15625) + (0.03125) = 0.8125

8 0
3 years ago
An auctioneer sold a herd of cattle whose minimum weight was 920 ​pounds, median was 1160 ​pounds, standard deviation 76​, and I
katen-ka-za [31]

Answer:

minimum = $445

median = $565

standard deviation = $38

IQR = $48

Step-by-step explanation:

The minimum and the median are measures of location and are affected during addition (or subtraction) and multiplication (or division).

Satandard deviation and IQR (inter-quartile range), which are measures of dispersion, are affected by only multiplication (or division).

For the weight,

<em>minimum </em>= 920 pounds

<em>median </em>= 1160 pounds

<em>standard deviation</em> = 76 pounds

<em>IQR </em>= 96 pounds

For the price,

<em>minimum </em>= 0.50(920) - 15 = $445

<em>median </em>= 0.50(1160) - 15 = $565

<em>standard deviation</em> = 0.50(76) = $38............(<em>Subtraction discarded</em>)

<em>IQR </em>= 0.50(96) = $48........................................(<em>Subtraction discarded</em>)

7 0
3 years ago
Question 28 plz because i don’t know how to do it with explanation plz
Nat2105 [25]

Answer:

do we find the value of unknown angle ?

7 0
3 years ago
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