1/4 (3s-14)=4 tell me how you solved it
1 answer:
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Answer:
Given :
ABC is a right triangle in which ∠ABC = 90°,
Also, Legs AB and CB are extended past point B to points D and E,
Such that,
To prove :
Proof :
In triangles AEC and EBA,
∠EAC= ∠ABE ( right angles )
∠CEA = ∠AEB ( common angles )
By AA similarity postulate,
,
Similarly,
Now, In triangles ADC and CBD,
∠ACD = ∠CBD ( right angles )
∠ADC= ∠BDC ( common angles )
By AA similarity postulate,
,
Similarly,
From equations (1) and (2),
The corresponding sides of similar triangles are in same proportion,
Hence, proved....
