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Scilla [17]
3 years ago
6

Find the length of XZ geometry help

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0
So all the sides are equal so you'd want to set 2x = (5/2)x - 5. then solve the equation and x = 10

to solves the equation first subraxt (5/2)x from both sides and you wnd up with -0.5x = -5 then divide by -0.5 to get x = 10
hope this helped!
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Which situation shows a constant rate of change?
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C is right I thinkkkk
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3 years ago
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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
What os the value of x in the equation 3x- 1/9y=18, when y =27
ollegr [7]
<span>3x- 1/9 y=18
</span><span>3x- 1/9(27) =18
3x - 3 = 18
3x = 21
  x = 7

hope it helps</span>
6 0
3 years ago
In the figure below, L N equals 4 x minus 7 and M O equals 2 x plus 13. For which value of x is the figure a rectangle?
Georgia [21]

For this case we have the following data:


LN = 4x-7

MO = 2x + 13

So that the figure can be a rectangle, its diagonals must be equal, that is, LN = MO

In this way we have:


4x-7 = 2x + 13

Clearing x we have:

4x-2x = 13 + 7 \\2x = 20

x=\frac{20}{2} \\x = 10

Thus, x must be equal to 10 so that the figure is a rectangle.


Answer:


x = 10

Option A

3 0
3 years ago
If a cannonball is shot directly upward with a velocity of 160 ft per​ second, its height above the ground after t seconds is gi
Contact [7]

Step-by-step explanation:

If a cannonball is shot directly upward with a velocity of 160 ft per​ second. Its height as a function of time is given by :

h(t)=160t-16t^2 .......(1)

t is in seconds

(a) Velocity is given by :

v=\dfrac{dh}{dt}\\\\v=\dfrac{d(160t-16t^2)}{dt}\\\\v=(160-32t)\ ft/s  

Acceleration is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(160-32t)}{dt}\\\\a=-32\ ft/s^2

(b) For maximum height put \dfrac{dh}{dt}=0

i.e.

160-32t=0\\\\t=5\ s

Put t = 5 s in equation (1). So,

h(5)=160t-16t^2\\\\h(5)=160(5)-16(5)^2\\\\h(5)=400\ ft

(c) When the ball reaches ground, its height is equal to 0. So,

h(t) = 0

160t-16t^2=0\\\\t(160-16t)=0\\\\t=0,t=10\ s

Hence, this is the required solution.

4 0
3 years ago
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