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Aleksandr [31]
3 years ago
14

An ounce of pine nuts cost $1.40 if Ellen buys 2.5 ounces of pine nuts, how much will she have to pay

Mathematics
2 answers:
Sauron [17]3 years ago
5 0
The answer is three dollars and fifty cents

GenaCL600 [577]3 years ago
5 0
<span>An ounce of pine nuts cost $1.40 if Ellen buys 2.5 ounces of pine nuts, how much will she have to pay?
</span>
One ounce cost $1.40, she needed 2 and a half ounces so. 

1.40
x 2.5
=$3.50

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We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab
777dan777 [17]

Answer:

(a) The distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

(c) The value of P(\bar X>0.50) is 0.50.

Step-by-step explanation:

It is provided that random variables X_{i} are independent and identically distributed Bernoulli random variables with <em>p</em> = 0.50.

The random sample selected is of size, <em>n</em> = 100.

(a)

Theorem:

Let X_{1},\ X_{2},\ X_{3},...\ X_{n} be independent Bernoulli random variables, each with parameter <em>p</em>, then the sum of of thee random variables, X=X_{1}+X_{2}+X_{3}...+X_{n} is a Binomial random variable with parameter <em>n</em> and <em>p</em>.

Thus, the distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

The sample size is large, i.e. <em>n</em> = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu=p=0.50

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05

(c)

Compute the value of P(\bar X>0.50) as follows:

P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\

                    =P(Z>0)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the value of P(\bar X>0.50) is 0.50.

8 0
3 years ago
Hi quick whats 18 x 1.25 <br> step by step !!
Ivan

Answer:

22.5

Step-by-step explanation:

125

x 18

---------

1. first set up your problem

2 4

125

x 18

------

1000

2. next multiply the 8 by 5 getting 40, drop the 0 anf move the 4 to the top above 2.

3. multiply 8 by 2 getting 16, then add the 4 you have ontop of the 2 to the 16 getting 20. Drop the 0 and bring the 2 over and place it above the one.

4. multiply 8 by 1 getting 8 then add the 2 above the 1 to 8 getting 10. Then put the ten infront of the tw zeros. 1000

125

x 18

--------

1000

0

Next add a 0 as a place filler under the 0 at the end.

125

x 18

-------

1000

1250

Then multiply the 1 by 5, then 1 by 2, then finnaly 1 by 1, getting you 1250.

1000

+1250

add together

getting 2250

then move 2 decimal places over to get 22.5

3 0
3 years ago
Solutions for 2x^2+18x=20, worth a TON, please only 100% answers ! Thank u !
victus00 [196]

Answer:

The solution of the given quadratic equation is 1 and (-10).

Step-by-step explanation:

2x^2+18x=20

x^2+9x=\frac{20}{2}

x^2+9x-10=0

ax^2+bx+c=0

Solving equation by quadratic formula:

Here , a = 1,b = 9, c = (-10)

D=b^2-4ac=(9)^2-4(1)(-10)=121

x=\frac{-b+{\sqrt{D}}}{2a}=\frac{(-9)+\sqrt{121}}{2(1)}=1

x=\frac{-b-{\sqrt{D}}}{2a}=\frac{(-9)-\sqrt{121}}{2(1)}=(-10)

The solution of the given quadratic equation is 1 and (-10).

5 0
3 years ago
two planes travel a constant speed. plane A travels 2.800 miles in 5 hours plane B travels 3.885 miles in 7 hours. which plane i
vfiekz [6]
Plane a is faster

Have a good day!!!
3 0
3 years ago
X + y = 17<br> -x + 3y 7-8<br> :
ladessa [460]

Answer:

it could be x= 10 and y=7? I think bc 17 can be split up into 10 and 7 or 9 and 8 etc.

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2 years ago
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