Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
Answer:
The scale is not reasonable.
Step-by-step explanation:
The painting is 48 inches by 120 inches
The scale is 1 inch = 4 inches
Divide the painting size by 4
48/4 = 12 inches
120/4 = 30 inches
We would need paper that is
12 inches by 30 inches
Our paper is 12 inches by 24 inches
It is too small. The scale is not reasonable
Answer:
-0.39mL
Step-by-step explanation:
Let x be the number.
The expression would be: 0.40 + x = 0.01
Apply algebra to the equation to solve for x. You can subtract 0.40 from each side to simplify the expression. Here's what it should look like after applying algebra: x = -0.39
Therefore the answer is -0.39mL
If it is parallel lines cut by a transversal then they are probably equal. Alternate exterior.
(4h+2)(2h+8)
4htines 2h= 8h^2
4htimes8=32h
2 times 2h=4h
2 times 8=16
Add Middle two you have
8h^2+36h+16
