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zimovet [89]
2 years ago
5

Two boats left a base camp at bearing of S60°E and S50°W at speeds of 50km/h and 70km/h respectively. Find the distance between

the both boats after two hours.
Mathematics
1 answer:
ivolga24 [154]2 years ago
7 0

Answer:

  • 197.93 km

Step-by-step explanation:

Let the base camp is point A and boats' locations after two hours are points B and C.

By connecting the three points together we get a triangle ABC with sides:

  • AB = 50*2 = 100 km
  • AC = 70*2 = 140 km

The angle between AB and AC is:

  • 60 + 50 = 110 degrees (opposite directions from south)

We are looking for the distance BC, which can be found by using the law of cosines:

  • BC² = AB² + AC² - 2AB*AC*cos ∠BAC
  • BC² = 100² + 140² - 2*100*140*cos 110°
  • BC²  = 39176.56 (rounded)
  • BC = √39176.56 = 197.93 km (rounded)

The distance between the boats is 197.93 km.

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The fare of $(20 - 2.5) = $17.5 will maximize the total fare.

<h3>What is Differentiation?</h3>

Differentiation means the rate of change of one quantity with respect to another. The speed is calculated as the rate of change of distance with respect to time.

Here, The operator for a round-trip fare of $20, carries an average of 500 people per day.

It is estimated that 20 fewer people will take the trip, for each $1 increase in fare.

for $x  increase in fare, 20x less people will take the trip and at that time the total fare F is given by  

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