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salantis [7]
3 years ago
8

Write the quadratic equation whose roots are 6 and -5, and whose leading coefficient is 3

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

y= 3x^2-3x-90

Step-by-step explanation:

Intercepts form of quadratic equation is

y= a(x-p) (x-q) where 'a' is the leading coefficient

p  and q  are the roots

Given that 6  and -5  are the roots

so p = 6  and q= -5

Leading coefficient a= 3

Plug in all the values in the equation

y= a(x-p) (x-q)

y= 3(x-6) (x-(-5))

y= 3(x-6) (x+5)

Now we  multiply the parenthesis

y= 3(x^2+5x-6x-30)

y= 3(x^2-x-30)

Multiply 3 inside the parenthesis

y= 3x^2-3x-90

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Answer:

  • D. 9

=========================

<h2>Given </h2>

Triangle with:

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  • Midsegment of 39.

<h2>To find</h2>

  • The value of n.

<h2>Solution</h2>

As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.

So we have:

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Solve it for n:

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Correct choice is D.

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1 year ago
Solve the equation cos (x/2) = cos x + 1. what are the solutions on the interval 0° ≤ x &lt; 360°?
Sedbober [7]

Answer:

Step-by-step explanation:

cos (x/2)=cos x+1

cos (x/2)=2cos ²(x/2)

2 cos²(x/2)-cos (x/2)=0

cos (x/2)[2 cos (x/2)-1]=0

cos (x/2)=0=cos π/2,cos (3π/2)=cos (2nπ+π/2),cos(2nπ+3π/2)

x/2=2nπ+π/2,2nπ+3π/2

x=4nπ+π,4nπ+3π

n=0,1,2,...

x=π,3π

or x=180°,540°,...

180°∈[0,360]

so x=180°

or

2cos(x/2)-1=0

cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)

x/2=360n+60,360n+300

x=720n+120,720n+300

n=0,1,2,...

x=120,300,840,1020,...

only 120° and 300° ∈[0,360°]

Hence x=120°,180°,300°

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2 years ago
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Answer:

Step-by-step explanation:

slope m= (y2-y1) / (x2-x1) = 15-12 / 4-4 = 3/0 is undefined since we can not divide by 0

slope is undefined so the line is vertical

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Which equation represents the function graphed on the coordinate plane?
Ulleksa [173]

Answer:

The two lines connect at (-4,-10)This means you would add 4 to x and then subtract 10 from the equation.

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