I think it’s 25 and two half’s
Answer:
(0,2)
Step-by-step explanation:
the point where Oy intercepts the graph has x=0 and y= f(0)
so this is (0,2)
In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Answer:
357.46 meters squared
Step-by-step explanation:
16 x 12.2 x 1/2 = 97.6
12.2 x 10.6 = 64.66
97.6 x 3 = 292.8
292.8 + 64.66 = 357.46
