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4 years ago

Using the Distributive Property, the expression 9.78(4.3x + 5.15) simplifies to _____.

2 answers:

3 0

We know, Distributive property tells: a(b + c) = ab + bc
So, 9.78(4.3x + 5.15) = 42.054x + 50.367

In short, Your Answer would be Option B

Hope this helps!

Viefleur [7K]4 years ago

3 0

The answer is B
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Find the area of the triangle.<br> If necessary, round your answer to the nearest hundredth.

g100num [7]

Answer:

A = 1824 $in^{2}$

Step-by-step explanation:

$A=\frac{bh}{2} +bh=\frac{(48)(12)}{2} +(48)(32)=288+1536=1824in^{2}$

Hope this helps

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2 years ago

Given: ∠ A = ∠ C, E is the midpoint of AC<br> Prove: △AEB △CED

bija089 [108]

Answer:

Step-by-step explanation:

3.AE = CE E is the midpoint of AC

4. ∠AEB = ∠CED Vertically opposite angles are equal

5. ΔAEB = ΔCED ASA congruence

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3 years ago

Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)

masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

$y=ax^2+bx+c$ ...(i)

It is passes through the point (0,11). So, substitute $x=0,y=11$ in (i).

$11=a(0)^2+b(0)+c$

$11=c$

Putting $c=11$ in (i), we get

$y=ax^2+bx+11$ ...(ii)

The quadratic function passes through the point (5,31). So, substitute $x=5,y=31$ in (ii).

$31=a(5)^2+b(5)+11$

$31-11=a(25)+5b$

$20=25a+5b$

Divide both sides by 5.

$4=5a+b$ ...(iii)

The quadratic function passes through the point (3,11). So, substitute $x=3,y=11$ in (ii).

$11=a(3)^2+b(3)+11$

$11-11=a(9)+3b$

$0=9a+3b$

Divide both sides by 3.

$0=3a+b$ ...(iv)

Subtracting (iv) from (iii), we get

$4-0=5a+b-3a-b$

$4=2a$

$\dfrac{4}{2}=a$

$2=a$

Putting $a=2$ in (iv), we get

$0=3(2)+b$

$0=6+b$

$-6=b$

Putting $a=2,b=-6$ in (ii), we get

$y=(2)x^2+(-6)x+11$

$y=2x^2-6x+11$

Therefore, the required quadratic equation is $y=2x^2-6x+11$ .

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3 years ago

3. How much money would you earn in three months (assume 4 weeks in each month) at each of the jobs you listed in #2 if you work

dedylja [7]

Answer:

I need only only only 0 rupees

5 0

3 years ago

Read 2 more answers

Please help! I’m confused (both questions, 24 & 25) I need to find all of the letters shown and show my work.

svlad2 [7]

Problem 24

<h3>Answer: w = 120</h3>

-----------------

Work Shown:

We have an isosceles triangle. The angles opposite the congruent sides are congruent. These are the base angles each 30 degrees. The missing angle is w. The three angles add to 180

(angle1)+(angle2)+(angle3) = 180

30+30+w = 180

60+w = 180

60+w-60 = 180-60 ... subtract 60 from both sides

w = 120

======================================================

Problem 25

<h3>Answers:</h3><h3>x = 6.5</h3><h3>y = 5</h3>

-----------------

Work Shown:

The angle marks are all the same, so the three angles are congruent to one another. We consider this an equiangular triangle. Any equiangular triangle is also equilateral, meaning all three sides are the same length.

So,

2x-5 = 8

2x-5+5 = 8+5 ... add 5 to both sides

2x = 13

2x/2 = 13/2 ... divide both sides by 2

x = 6.5

and also,

y+3 = 8

y+3-3 = 8-3 ... subtract 3 from both sides

y = 5

3 0

3 years ago