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2 years ago

6

Given: ∠ A = ∠ C, E is the midpoint of AC Prove: △AEB △CED

1 answer:

bija089 [108]2 years ago

4 0

Answer:

Step-by-step explanation:

3.AE = CE E is the midpoint of AC

4. ∠AEB = ∠CED Vertically opposite angles are equal

5. ΔAEB = ΔCED ASA congruence

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Identify which equations have one solution, infinitely many solutions, or no solution.

notsponge [240]

First one= x=5
second one= x=1/30 or 0.03 or 30^-1
third one= All real numbers or R
fourth one= No solution
Fifth one= All real numbers or R
Sixth one= p=-10/3 or -3 1/3 or -3.3

R is just the symbol for all real numbers. Also know as infinitely many solutions.

Hope this helps ! :) have a good day! Make sure you eat.

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2 years ago

PLEASE HELP ME!!! Which inequality best represents that ice cream at -5 degrees celsius is cooler than 4 degrees celsius? A. -4

otez555 [7]

Answer:

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Step-by-step explanation:

I just think it is

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3 years ago

Find the slope of the line passing through the given points (7, 13) and (2, -12).

tatyana61 [14]

Answer:

The answer is C.

Step-by-step explanation:

m=y²-y¹/x²-x¹

m=(-12)-13/2-7

m=-25/-5

m=5

4 0

2 years ago

Evaluate (x + y)0 for x = -3 and y = 5.<br><br> a.) -1/2<br> b.) 0<br> c.) 1<br> d.) 2

lions [1.4K]

Answer is B. No matter what the x or y will be the result will be 0. Anything multiplied by 0 is equal to 0.

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3 years ago

Read 2 more answers

Write the equation of a line perpendicular to y=0.25x-7 and passes through the point -6,8

horrorfan [7]

the equation of a line perpendicular to $y=0.25x-7$ and passes through the point (-6,8) is $y=-4x+30$

Step-by-step explanation:

We need to write equation of line perpendicular to $y=0.25x-7$ and passes through the point (-6,8)

Since the line $y=0.25x-7$ is in slope-inetercept form $y=mx+b$

the slope of line m = 0.25

As, the new line is perpendicular to the given line so, slopes of lines that are perpendicular are: slope = -1/slope1

So, slope will be -1/0.25 = -4

Now, finding y-intercept.

$y=mx+b8=4(-6)+b\\8=-24+b\\b=8+24\\b=30$

So, value of y-intercept b = 30

Now the equation of the required line having slope m= -4 and b =30 will be:

$y=mx+b\\y=-4x+30$

So, the equation of a line perpendicular to $y=0.25x-7$ and passes through the point (-6,8) is $y=-4x+30$

Keywords: Equation of line, slope-intercept form

Learn more about slope-intercept form at:

#learnwithBrainly

3 0

3 years ago