This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
Look at Step by step
Step-by-step explanation:
Mean: (a) 1.38
Mean: (b) 1.7
median (a) 1.3
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You should try reading notes you took during your class period.
<h3>The equation is:</h3><h3>
</h3><h3>The number is 3 or 4</h3><h3><em><u>Solution:</u></em></h3>
Given that,
7 added to the square of a number is equal to 7 times the number, minus 5
Let "x" be the unknown number
From given,
7 added to square of x = 7 times the x minus, 5
Solve the above equation
Split the middle term
We have two solutions
x - 3 = 0
x = 3
And
x - 4 = 0
x = 4
Thus number is 3 or 4
