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enot [183]
3 years ago
10

When x = 2, y = 50 and when x = 4, y = 100. Which direct variation equation can be used to model this function?

Mathematics
2 answers:
Taya2010 [7]3 years ago
8 0
Y=25x because if you were plug in the x for both equations:

y=25 (2)
y=50

y=25 (4)
y=100

It would be the same value as y.
hjlf3 years ago
5 0

The answer is y=25x


bc 25x2=50 and 25x4=100

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Solve the differential equation by variation of parameters.<br><br> y''+y=secx
suter [353]

Answer:y=

Acosx+Bsinx +cosx ln(cosx)+x sinx

Step-by-step explanation:

given  equation y''+y=secx

auxiliary  equation

p^2+1=0\\p=\pm i

so CF is y=Acosx+Bsinx

now

y_1(x)=cosx \ \ \ \ y_2(x)=sinx\\{y_1}'(x)=-sinx \ \ \ \ {y_2}'(x)=cosx

using wronskian formula

W=\begin{vmatrix}cosx &sinx \\ -sinx & cosx\end{vmatrix}

          =cos^2x+sin^2x=1

now f(x)=secx

u=-\int \frac{f(x)y_2(x)}{W(x)}dx \ and \ v=\int \frac{f(x)y_1(x)}{W(x)}dx

u=-\int \frac{secx\times sinx}{1}dx \ and \ v=\int \frac{secx\times cosx}{1}dx

u=-\int tanx dx \ and \ v=\int {1}dx

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now particular integrals are

PI=cosx ln(cosx)+x sinx

total solution

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8 0
3 years ago
Convert 3/75 to a decimal , then to a percent
jek_recluse [69]
Firstly we need to simplify it:

3/75 = 1/25

We know that 1/25 is as much as 4/100 which can be written as 0,04.

Also 0,04 is as much as 4%.

I hope it'll help you :)
3 0
3 years ago
Geometry one help please!
12345 [234]
What is the question?
3 0
2 years ago
A warehouse worker fills 150 orders per day on average. From day to day, the number of orders varies by 2%. What is the range of
choli [55]

Answer:

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Step-by-step explanation:

orders varies by 2% means that orders can be LOWER THAN THE AVERAGE, or HIGHER THAN THE AVERAGE.

That is, by 2%.

First, we need to find the decimal of 2%, so

2/100 = 0.02

We multiply this with the average number of order, 150, to get the varying amount:

0.02 * 150 = 3

Thus, the range would be:

150 - 3 = 147

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5 0
3 years ago
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Anna007 [38]

Answer:

h=0.4

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h=0.4

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2 years ago
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