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ch4aika [34]
3 years ago
11

Don’t understand please help asap

Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

First you have to solve both inequalities,

3x-1>8

3x>9

x>3

and the other one

2x≤4

x≤2

then you graph each one on the number line

the graph says or, so the solution can satisfy either equation

the solution would be all real numbers except three

the way to write it is x≠3

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qaws [65]

Answer:

<h2>23.6°</h2>

Step-by-step explanation:

<h3>to understand the solving steps</h3><h3>you need to know about</h3>
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  • PEMDAS
<h3>given:</h3>
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<h3>to find:</h3>
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<h3>let's solve:</h3>

let \: xyz \: angle \: be \:  \alpha

according \: to \: the \: question

\sin( \alpha )  =  \frac{xy}{zy}

\sin( \alpha )  =  \frac{6}{15}

\alpha  = asin( \frac{6}{15} )

\alpha  =  {23.6}^{o}

therefore

<h3>xyz angle=23.6°</h3>
8 0
3 years ago
How do you find the area of the shaded region
Amiraneli [1.4K]

well, first off, let's notice that we have a trapezoid with a rectangle inside it, so the rectangle is really "using up" area that the trapezoid already has.

now, if we just get the area of the trapezoid, and then the area of the rectangle alone, and then subtract that area of the rectangle, the rectangle will in effect be making a hole inside the trapezoid's area, and what's leftover, is the shaded section, that part the hole is not touching.

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h&=height\\ a,b&=\stackrel{parallel~sides}{bases} \\\cline{1-2} h&=8\\ a&=16\\ b&=8 \end{cases}\implies A=\cfrac{8(16+8)}{2}\implies A=96 \\\\\\ \stackrel{\textit{area of the rectangle}}{(5\cdot 3)\implies 15}~\hfill \stackrel{~\hfill \textit{shaded area}}{\stackrel{\textit{trapezoid}}{96}~~ - ~~\stackrel{\textit{rectangle}}{15}~~ = ~~81}

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9514 1404 393

Answer:

  1 1/5 hours walking to 1 hour jogging

Step-by-step explanation:

You can multiply by 3 to eliminate the fraction, then reduce in the usual way.

  4 ÷ (3 1/3)

  = 12 ÷ 10 . . . . . . . multiply both numbers by 3

  = 1 2/10 = 1 1/5 . . . . do the division by 10

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