Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
Answer:
there will be 16 bags
Step-by-step explanation:
Answer:
$92.60
Step-by-step explanation:
7($5.99) + 7($6.49)=$41.93
$41.93 + $45.43 = $87.36
$87.36 + ($87.36 × 6%=0.06)
$87.36 + (0.06 × $87.36=5.24)
$87.36 + $5.24= $92.60
