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tatiyna
3 years ago
12

A=1/2h(b1+b2) solve for b2. How on earth do I do this?

Mathematics
1 answer:
storchak [24]3 years ago
8 0
To eliminate the fraction, multiply by 2 both sides of the equation. This gives,
                                     2A = h x (b1 + b2)
Then, divide both the left hand and the right hand side of the equation by the variable h.
                                 2A / h = b1 + b2
Next, subtract b1 from both sides,
                                (2A / h) - b1 = b2
Rearranging  the equation,
                                        b2 = (2A/h) - b1
 
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If you simplify the equations and the left side is identical to the right side, then there are an infinite number of solutions: the equation is true for all values of x.

Another way to simplify the equation is to subtract the right side from both sides. If that simplifies to 0 = 0, then there are an infinite number of solutions.

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See in the explanation

<h2>Explanation:</h2>

In this exercise, <em>we have the following points:</em>

(0.8) \\ \\ (6.4)

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(1) \ y=-x+8 \\ \\ (2) \ y=\frac{3}{2}x+6 \\ \\ (3) \ y=-\frac{4}{5}x+4 \\ \\ (4) \ y=\frac{1}{2}x+8

When plotting these graphs, we find the following facts:

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We see the graph in the first figure below. The graph only passes through the point (0, 8)

<h3>For (2):</h3>

This is the second graph below. The graph passes neither through point (0, 8) nor (6, 4)

<h3>For (3):</h3>

This is the third graph below. The graph passes neither through point (0, 8) nor (6, 4)

<h3>For (4):</h3>

This is the fourth graph below. The graph only passes through the point (0, 8)

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<h2>Learn more:</h2>

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