Answer:
1/ 3
Step-by-step explanation:
If each of the cards is turned over, the probability of picking up a card of one type P(E) becomes equal to:
=> P(E) = number of cards of the required type/ total number of cards
● Total number of spades( ♤ ) = 3
{the queen, one ace and the nine are all spades}
● Total number of cards = 6
Probability of drawing a spade= 3/ 6
= 1/ 2
● Total number of "7" = 1
● Total number of cards = 6
Probability of drawing a 7
= 1/ 6
Now, what's asked is the difference in the probabilities of drawing a spade and a seven.
= 1/ 2 - 1/ 6
= 3/ 6 - 1/ 6
= 2/ 6
= 1/ 3
Hence, 1/ 3 of a greater chance of drawing a spade over a 7.
The answer is 3 if I’m not mistaken
Answer:
Step-by-step explanation:
stupid enough
y=mx+b
slope = 16-12/3-6
-4/3
plug in x and y
16=-4/3(3)+b
b=20
<h2><em><u>Red</u></em></h2>
Answer:
divied the first 3
Step-by-step explanation:
if the number is next to another multiply
