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3 years ago

Shadé is organizing the members of a

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

7 0

Answer:

there will be eight rows

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Solve equations for x/7-1=8

denpristay [2]

x/ 7 - 1 = 8 -Subtract 1 from 7

x / 6 = 8 -Multiply both sides by 6

x = 48

Check:

48 / 7 - 1 = 8

48 / 6 = 8

8 = 8

Hope this helps!

3 0

3 years ago

What is the answer?

Vika [28.1K]

Answer:

Step-by-step explanation:

7 0

3 years ago

How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

3 years ago

Which equation could have been used to create this graph

Temka [501]

Answer:

The answer is A

Hoped it helped <3 tell me if I am wrong

Step-by-step explanation:

4 0

3 years ago

On the first play during the football game our team gained 5 yards. Between both the second and third play our team lost eight y

Maurinko [17]

Answer:

loss

Step-by-step explanation:

you might want to check someone else answer first tho

7 0

3 years ago