Factor n^2+5n-24. Show that the original polynomial and the factored from describe the same sequence of numbers for n=0,1,2,3,an
d 4
1 answer:
Step-by-step explanation:
We have the original equation n ^ 2 + 5 * n - 24, when factoring we have:
(n + 8) * (n - 3)
Now by replacing the values:
n = 0
0 ^ 2 + 5 * 0 - 24 = - 24
(0 + 8) * (0 - 3) = - 24
n = 1
1 ^ 2 + 1 * 0 - 24 = - 18
(1 + 8) * (1 - 3) = -18
n = 2
2 ^ 2 + 5 * 2 - 24 = - 10
(2 + 8) * (2 - 3) = - 10
n = 3
3 ^ 2 + 5 * 3 - 24 = 0
(3 + 8) * (3 - 3) = 0
n = 4
4 ^ 2 + 5 * 4 - 24 = 12
(4 + 8) * (4 - 3) = 12
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