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lianna [129]
3 years ago
7

What’s is the product of the two solutions of the quadratic equation ax^2+bx+c=0

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

The product of the two roots is c/a.

_____

Consider the equation

... a(x -p)(x -q) = 0

which has solutions x=p and x=q.

When multiplied out, it becomes ...

... a(x² -(p+q)x +pq) = ax² -a(p+q)x +apq = 0

When apq = c, the product pq is c/a.

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A salesperson's weekly paycheck is 10% more than a second salesperson's paycheck. The two paychecks total $1525. Find the amount
Kaylis [27]
1525 ➗ 2 = 762.5
762.50 x 10% is 76.25
762.50 - 76.25 = 686.25
one paycheck is 762.50
the other is 686.25

I hope this helps.
6 0
3 years ago
I need help with this ^
Nady [450]
<h3>Answer is 20 </h3>

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A tomato plant grew an average of 0.06 m per day. How many days did it take for the plant to grow a total of 0.96 m.            
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3 0
3 years ago
Read 2 more answers
Margie says the set of numbers, 0.1, -1, -21
rjkz [21]

Answer:

-21, -1, 0.1, 3, 4

Step-by-step explanation: the higher the negative number is the lower the number is for example -30 is lowe then -1

4 0
3 years ago
Read 2 more answers
1. Find the distance between two
BigorU [14]

Answer:

\mathrm{D)\:}9.4\: \mathrm{units}

Step-by-step explanation:

<u>Solution 1:</u>

Notice the x coordinate of both points are equal, meaning both points are on a vertical line. The distance between two points on a vertical line is the absolute difference of their y-coordinates. The absolute difference between 4.7 and -4.7 is |4.7-4.7|=\fbox{$9.4$}.

<u>Solution 2:</u>

The distance between two points (x_1,y_1) and (x_2,y_2) is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Plugging in given values, we have:

d=\sqrt{(-2.6-(-2.6))^2+(4.7-(-4.7))^2},\\d=\fbox{$9.4$}.

8 0
2 years ago
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