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lianna [129]
3 years ago
7

What’s is the product of the two solutions of the quadratic equation ax^2+bx+c=0

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

The product of the two roots is c/a.

_____

Consider the equation

... a(x -p)(x -q) = 0

which has solutions x=p and x=q.

When multiplied out, it becomes ...

... a(x² -(p+q)x +pq) = ax² -a(p+q)x +apq = 0

When apq = c, the product pq is c/a.

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Add the equations.<br>2x-3y = -1<br>+ 3x + 3y= 26<br><br>​
hichkok12 [17]

Answer:

The answer in the procedure

Step-by-step explanation:

we have

2x-3y=-1 ----> equation A

3x+3y=26 --> equation B

Solve the system by elimination

Adds equation A and equation B

2x-3y=-1

3x+3y=26

----------------

2x+3x=-1+26

5x=25

x=25/5

x=5

Find the value of y

substitute the value of x in equation A or equation B and solve for y

2(5)-3y=-1

10-3y=-1

3y=10+1

y=11/3

8 0
3 years ago
Fiona, an avid food blogger posted a total 216 recipes in 36 weeks. If she posted them at a constant rate, how many recipes did
Cloud [144]

Answer:

90

Step-by-step explanation:

216/36= 6

6 times 15=90

Hope this helped

:)

5 0
3 years ago
Read 2 more answers
A store has a coupon for $10 off and a discount of 20%. Write a function for the coupon. Use x for the original price and C for
Ludmilka [50]
<h2>Explanation:</h2><h2></h2>

We know some facts:

  • x for the original price.
  • The store has a coupon for $10 off and a discount of 20%
  • C for the price after the coupon is applied.

So from the statement 2, you can realize there are two types of discounts:

  1. The discount offered by the coupon
  2. The discount offered by 20%

Since we need to write a function just for the coupon, then we don't include the discount offered as percentage, then we subtract the coupon from the original price:

\boxed{C=x-10}

8 0
3 years ago
Which is the range of the function f(x) =One-seventh(9)x?
shutvik [7]

Answer:

Option c: all real numbers greater than 0

Step-by-step explanation:

we have

f(x)=\frac{1}{7}(9^{x})

This is a exponential function of the form

f(x)=a(b^{x})

where

a is the initial value (y-intercept)

b is the base

r is the rate

b=(1+r)

In this problem we have

a=1/7

b=9

r=b-1 ----> r=9-1=8 -----> r=800%

using a graphing tool

see the attached figure

The domain is the interval ------> (-∞,∞)

The domain is all real numbers

The range is the interval ---------> (0,∞)

The range is all real numbers greater than zero

6 0
3 years ago
Read 2 more answers
158 divided by 37 I don’t get it what is the answer
Salsk061 [2.6K]

Answer:

4.2702702703

=

4 Remainder 10

Step-by-step explanation:

158 divided by 37 = 4.270

The result of 158/37 is a non-terminating, repeating decimal.

The repeating pattern above, 270, is called repetend, and denoted overlined with a vinculum.

This notation in parentheses is also common: 158/37 = 4.(270): However, in daily use it’s likely you come across the reptend indicated as ellipsis: 158 / 37 = 4.270… .

158 divided by 37 in decimal = 4.270

158 divided by 37 in fraction = 158/37

158 divided by 37 in percentage = 427.02702703%

Note that you may use our state-of-the-art calculator above to obtain the quotient of any two integers or decimals, including 158 and 37, of course.

Repetends, if any, are denoted in ().

The conversion is done automatically once the nominator, e.g. 158, and the denominator, e.g. 37, have been inserted.  

7 0
3 years ago
Read 2 more answers
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