Question

Miguel biked 14 km in the same amount of time that linda hiked 10 km. Miguel's rate was 4 km/h more than linda's. How fast did each travel

Answer 1

The first thing we must do is define a variable.

We have then:

x: Linda's speed.

Then, by definition, the time traveled is equal to the distance between the velocity.

We have then:

For Linda:

$t = \frac{10}{x}$

For Miguel:

$t = \frac{14}{x + 4}$

Then, since time is the same, then:

$\frac{10}{x} = \frac{14}{x + 4}$

Clearing Linda's speed we have:

$10 (x + 4) = 14x$

$10x + 40 = 14x$

$40 = 14x-10x$

$40 = 4x$

$x = \frac{40}{4}$

$x = 10$

Then, Miguel's speed is:

$x + 4 = 10 + 4 = 14$

Answer:

Linda's speed is 10 Km/h

Miguel's speed is 14 Km/h