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Greeley [361]
3 years ago
15

Over 4 days the temperature was 4,6,-12,and -5 degrees.What was the average temperature?

Mathematics
1 answer:
Deffense [45]3 years ago
8 0
The average temperature is -7.



Hope this helps
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Cuanto es 3 octavos menos 1 octavo
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3 years ago
Factor the polynomial completely. b^6-3b^4-2b^2+6
artcher [175]

Answer:

(b^2 - 3) (b^4 - 2)

Step-by-step explanation:

b^6-3b^4-2b^2+6

Break into 2 parts:

b^6-3b^4 = b^4(b^2 - 3)

-2b^2+6 = -2(b^2 - 3)

Put these 2 together:

(b^2 - 3) (b^4 - 2)

7 0
2 years ago
(x - 1/3)-1/4=25 Help me please
Scorpion4ik [409]

Answer:

x=\frac{307}{12}

Step-by-step explanation:

combine like terms

\frac{-1}{3} - \frac{1}{4} = \frac{-7}{12}

x-\frac{-7}{12}=25

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x= \frac{307}{12}

hope this helps

5 0
4 years ago
You spin the spinner and flip a coin. Find the probability of the compound event.
Andrews [41]

Answer:

1/10.

Step-by-step explanation:

Prob(Spinning a 1) = 1/5.

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Probability of a 1 then a head = 1/5 * 1/2 = 1/10.

Note: we multiply the probabilities because the 2 events are independent.

4 0
3 years ago
If a || b, m∠2 = 63°, and m∠9 = 105°, find the measure of each missing angle.
Ne4ueva [31]

Given that a || b, m∠2 = 63° and m∠9 = 105°.

Now, all the angles are as follows:

m∠5= m∠2 = 63° [vertically opposite angle]

m∠7= m∠9=105° [vertically opposite angle]

m∠8= 180°-m∠9=180°-105°=75° [Supplementry angles, m∠8+m∠9=180°]

m∠10= m∠8= 180° [vertically opposite angle]

m∠6= m∠8=75° [ Alternate angles]

m∠3= m∠6=75° [vertically opposite angle]

m∠1= 180°-(m∠2+m∠3)=180°-(63°+75°)=42° [as m∠1+m∠2+m∠3=180°]

m∠4= m∠1=42° [vertically opposite angle]

m∠11=m∠4=42° [ Alternate angles]

m∠13= m∠11=42° [vertically opposite angle]

m∠12= 180°-m∠11=180°-42°=138° [as m∠8+m∠9=180°]

m∠14 = m∠12=138° [vertically opposite angle]

4 0
3 years ago
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