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murzikaleks [220]
2 years ago
14

378 minutes = 6 hours 3 minutes True or false How would I figure this out

Mathematics
2 answers:
olganol [36]2 years ago
8 0
Hai the statement is incorrect because 378 minutes equals 6 Hours and 18 minutes. This is because 1 hour is 60 minutes 60 times 6 equals 360 then add 18 and that equals 378 minutes. This is why 6 hours and 18 minutes is correct instead of 6 hours and 3 minutes.
GrogVix [38]2 years ago
5 0
This is incorrect.  Divide 378/60 and the quotient is the number of hours while the remainder is the minutes.  In  this case, it is 6 hours and 18 minutes.  Please mark Brainliest!!!
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2 years ago
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Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
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Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
3 years ago
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In a quality control test of parts manufactured at Dabco Corporation, an engineer sampled parts produced on the first, second, a
sammy [17]

Answer:

p value = 0.0174

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Step-by-step explanation:

Thinking step:

We need to perform a test to determine if the proportion of the good parts is the same for all three shifts at a significance level of \alpha = 0.05

Assumption : all the population for each or the three shifts is not equal.

Calculation:

Let p₁ be the sample of the first shift

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According to the null hypothesis

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In other words, all the population sample proportions are equal.

Alternatively, we can assume that the three shift are not equal p₁ ≠ p₂ ≠ p₃

Tabulating and performing the \chi² test gives 8.10

degrees of freedom:

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Thus the degree of freedom is 2

Solving using the MINITAB software gives: p = 0.174

The solution shows that the p value < level of significance, then p-value lies in the range 0.0174≤\alpha≤0.05

Therefore, we reject the null hypothesis based on the fact that the three shifts are not equal.

5 0
2 years ago
A skier is trying to decide whether or not to buy a season ski pass. A daily pass costs ​$69. A season ski pass costs ​$350. The
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Divide the season pass cost by the daily capstone:

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7 0
3 years ago
Jim buys a car for $22,500. He decides to finance through the dealership at 3.5% simple interest for 5.5 years. How much interes
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Answer:

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