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murzikaleks [220]

3 years ago

14

378 minutes = 6 hours 3 minutes True or false How would I figure this out

2 answers:

olganol [36]3 years ago

8 0

Hai the statement is incorrect because 378 minutes equals 6 Hours and 18 minutes. This is because 1 hour is 60 minutes 60 times 6 equals 360 then add 18 and that equals 378 minutes. This is why 6 hours and 18 minutes is correct instead of 6 hours and 3 minutes.

GrogVix [38]3 years ago

5 0

This is incorrect. Divide 378/60 and the quotient is the number of hours while the remainder is the minutes. In this case, it is 6 hours and 18 minutes. Please mark Brainliest!!!

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Determine the slope and the y-intercept of the line represented by the equation y= -7/3×+3 slope: 7/9 ;y-intercept: 3 slope: 9/7

Mademuasel [1]

Answer:

$slope ⟹ \: - \frac{7}{9} \\ y \: intercept⟹ \: 3$

Step-by-step explanation:

The standard form of this equation is

$y = mx + c \\$

m stands for the gradient or the slope, and c represents the y-intercept

$y = mx + c \\ y = - \frac{7}{9} x + 3 \\ m = - \frac{7}{9} \: \\ and \: \\ \: y \: intercept \: = 3$

7 0

2 years ago

100 points! Mhanifa can you please help? Look at the picture attached. I will mark brainliest!

dimulka [17.4K]

Answer:

1 and 2.

Midpoints calculated, plotted and connected to make the triangle DEF, see the attached.

D= (-2, 2), E = (-1, -2), F = (-4, -1)

3.

As per definition, midsegment is parallel to a side.

Parallel lines have same slope.

<u>Find slopes of FD and CB and compare. </u>

m(FD) = (2 - (-1))/(-2 -(-4)) = 3/2
m(CB) = (1 - (-5))/(1 - (-3)) = 6/4 = 3/2
As we see the slopes are same

<u>Find the slopes of FE and AB and compare.</u>

m(FE) = (-2 - (- 1))/(-1 - (-4)) = -1/3
m(AB) = (1 - 3)/(1 - (-5)) = -2/6 = -1/3
Slopes are same

<u>Find the slopes of DE and AC and compare.</u>

m(DE) = (-2 - 2)/(-1 - (-2)) = -4/1 = -4
m(AC) = (-5 - 3)/(-3 - (-5)) = -8/2 = -4
Slopes are same

4.

As per definition, midsegment is half the parallel side.

<u>We'll show that FD = 1/2CB</u>

FD = $\sqrt{(2+1)^2+(-2+4)^2}$ = $\sqrt{3^2+2^2}$ = $\sqrt{13}$
CB = $\sqrt{(1 + 5)^2+(1+3)^2}$ = $\sqrt{6^2+4^2}$ = 2 $\sqrt{13}$
As we see FD = 1/2CB

<u>FE = 1/2AB</u>

FE = $\sqrt{(-4+1)^2+(-1+2)^2}$ = $\sqrt{3^2+1^2}$ = $\sqrt{10}$
AB = $\sqrt{(-5 -1)^2+(3-1)^2}$ = $\sqrt{6^2+2^2}$ = 2 $\sqrt{10}$
As we see FE = 1/2AB

<u>DE = 1/2AC</u>

DE = $\sqrt{(-2+1)^2+(2+2)^2}$ = $\sqrt{1^2+4^2}$ = $\sqrt{17}$
AC = $\sqrt{(-5 +3)^2+(3+5)^2}$ = $\sqrt{2^2+8^2}$ = 2 $\sqrt{17}$
As we see DE = 1/2AC

3 0

3 years ago

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denis-greek [22]

Answer:

$a^2+b^2-c^2+2ab$

Step-by-step explanation:

$(a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2=a^2+b^2-c^2+2ab$

Hope this helps!

5 0

3 years ago

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Xelga [282]

I belive the answer would be....
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3 years ago

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harkovskaia [24]

Answer:

10

13

15

17

22

Step-by-step explanation:

the first 5 terms will be 1,2,3,4 and 5.

I guess...

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3 years ago

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