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2 years ago

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1 answer:

5 0

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Another math question: You have 15 apples you friend gives you 15 more now withth the total of apples you have, you have to answ

jarptica [38.1K]

Answer:

27000

Step-by-step explanation:

(15+15)^3=27000

4 0

2 years ago

Read 2 more answers

The sum of the digits of a two-digit number is 9. If the digits are reversed,the new number is 9 more than the original number.F

hodyreva [135]

Answer:

Step-by-step explanation:

Let the original number be xy where y is unit and x is tens hence original number is 10x+y When reversed, the new number is yz hence 10y+x

We know that the original number plus 9 is the reversed number hence

10x+y+9=10y+x

9y-9x=9 which when simplified we obtain that

y-x=1 equation 1

Originally, we are told that the sum of x and y is 9 hence

y+x=9 equation 2

Solving equation 1, it means y=x+1

Substituting the above into equation 2

x+1+x=9

2x=9-1

2x=8

x=8/2=4

Since y=x+1 then y=4+1=5

Therefore, the original number, xy is 45

4 0

3 years ago

The circumference of a circle is 60? cm. what is the length of an arc of 140'?

My name is Ann [436]

I hope this helps you

Circumference =2.pi.r

60=2.3,14.r

r=30/3,14

Arc Length = 140/360.2.3,14.30/3,14

Arc Length =70/3

3 0

2 years ago

4. Determine whether each equation defines y as a function of x.

tatuchka [14]

Answer:

I believe it is A!!!!!

Step-by-step explanation:

I took the test E2020

3 0

2 years ago

The sum of the first two terms of an infinite GP is 6 and each term is 5 times the sum of the succeeding termsthen the second te

kozerog [31]

Answer:

$\dfrac{6}{7}$ .

Step-by-step explanation:

It is given that the sum of first two terms of an infinite GP is 6.

nth term of a GP is

$a_n=ar^{n-1}$

$a+ar=6$ ...(1)

Each term is 5 times the sum of the succeeding terms.

$a_n=5(a_{n+1}+a_{n+2}+...+\infty)$

$ar^{n-1}=5(ar^n+ar^{n+1}+...+\infty)$

$ar^{n-1}=5ar^n(1+r+r^2+...+\infty)$

Divide both sides by a.

$r^{n-1}=5r^n(\dfrac{1}{1-r})$ $[\text{Sum of infinite GP}=\dfrac{a}{1-r}]$

$\dfrac{r^n}{r}=\dfrac{5r^n}{1-r}$

$\dfrac{1}{r}=\dfrac{5}{1-r}$

$1-r=5r$

$1=6r$

$\dfrac{1}{6}=r$

The common ratio is 1/6.

Put r=1/6 in (1).

$a+a(\dfrac{1}{6})=6$

$6a+a=36$

$7a=36$

$a=\dfrac{36}{7}$

Second term $ar=\dfrac{36}{7}\times \dfrac{1}{6}=\dfrac{6}{7}$

Therefore, the second term is $\dfrac{6}{7}$ .

4 0

2 years ago