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Naddik [55]
3 years ago
10

5, 392, 029, 004 in word form

Mathematics
2 answers:
Leona [35]3 years ago
5 0
5 billion three-hundred and ninety-two million twenty-nine thousand and four.
Tju [1.3M]3 years ago
3 0
Five billion three hundred and ninety-two million twenty nine thousand and four
You might be interested in
38÷244 ,24÷943,653÷52
jeka94
38/244= about 0.16
24/943= about 0.03
653/53= about 12.32
All answers are rounded
5 0
3 years ago
According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
When x 4, y = 1<br> х^2 + Зry — 7у^2<br><br><br> Can you explain the whole answer.
sineoko [7]
I couldn’t really understand the question but i did 4squared + 3r(1) - 7(1)squared and i got -33 + 3r
3 0
3 years ago
Help and explanation with this probability question would be really appreciated :)
GuDViN [60]

Answer:

b

Step-by-step explanation:

The probability (PB) is .4 or 4/10 or 2/5.

So, we'd do a proportion.

2/5=x/6

Cross multiply.

5x=12

Divide by sides by 5.

x=2.4

We round up to account for the .4

so b

I can't answer c right now, but I'll come back once my class is over :)

3 0
3 years ago
Mrs. Ross needs to buy dish soap. There are four differently sized containers. Sort the brands from least to the greatest unit p
r-ruslan [8.4K]

Answer: Spotless soap < Bright wash < Lemon bright < lot of suds

Step-by-step explanation:

Given that 8 oz of Lots of suds cost = $0.98

Then unit price of 1 lot of suds = 0.98/8 = $0.1225

Given that 12 oz of Bright wash cost = $1.29

Then unit price of 1 Bright wash = 1.29/12 = $0.1075

Given that 30 oz of Spotless soap cost = $3.14

Then unit price of 1 Spotless soap = 3.14/30 = $0.104666666667

Given that 32 oz of Lemon bright cost = $3.50Then unit price of 1 Lemon bright = 3.50/32 = $0.109375

We also need to round the values to the nearest thousandth means three digits after decimal

Then unit price of 1 lot of suds = $0.123

unit price of 1 Bright wash = $0.108

unit price of 1 Spotless soap = $0.105

unit price of 1 Lemon bright = $0.109

Now we can easily sort them

0.105 < 0.108 < 0.109 < 0.123

respective names in sorted order are:

Spotless soap < Bright wash < Lemon bright < lot of suds

8 0
3 years ago
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