Consider the equation:
Subtracting '4' from both the sides of the equation, we get as
Squaring on both the sides of the equation, we get
Subtracting '2' from both the sides of the equation, we get
x=14
Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.
Hence, it is not an extraneous solution.
X - 9 < 0
add 9 to both sides:-
x - 9 + 9 < 9
x < 9
x - 9 is negative for all values of x less that 9.
Answer:
1.
y = 20(11) + 300 = 520
y = 5(11)(11) = 605
y = 10(1.4)^11 = 404.96
hence the quadratic formula - y = 5x^2 has the largest y-value
2.
y = 20 (14) + 300 = 580
y = 5 (14) (14) = 980
y = 10(1.4)^ 14 = 1111.20 > this is greater than both equations above
14 is the smallest value of x for which the value of the exponential equation is greater than the values of both the linear and quadratic functions
Step-by-step explanation:
You would divide 228/12 = 19 per class.
