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2 years ago

Please help me write the equation for the problem below

1 answer:

8 0

Since you want both sides to equal each other, you can set up the following equation:

chess club members = computer club members

500 - 30x = 150 + 20x

x represents the amount of years that have passed. The coefficients for x represent the loss or gain of members per year.

Add 30x to both sides.

500 = 150 + 50x

Subtract 150 from both sides.

350 = 50x

Divide both sides by 50 to solve for x.

x = 7

It will take 7 years for both clubs to have the same amount of members.

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Which statement explains the type of function that is represented by the equation

eduard

Answer:

Step-by-step explanation:

The function has a variable that will make the graph curve up.

3 0

1 year ago

The points in the table lie on a line. Find the slope of the line

8090 [49]

Answer:

1/2

Step-by-step explanation:

Pick two of the x's and y's

The first two columns in the table, the x's are -2 and 0 and the y's are 3 and 4.

The x value changes as a +2 and the y value changes from a +1 from the first two columns. Put the +2 as the denominator and the +1 as the numerator. 1/2

5 0

2 years ago

Given that 2 x − 9 y = 22

aivan3 [116]

Answer:

y = -8/9

Step-by-step explanation:

2 ×(7) - 9 y = 22

14 - 9y = 22

9 y = -8

y = -8/9

3 0

2 years ago

four time the first of three consecutive integers is six more than the product of two and the third integer. find the integers.

maw [93]

<span>
Assign variables :
Let x = first consecutive even
Let x + 2 = second consecutive even
Let x + 4 = third consecutive even
4x = 6 + 2(x+4)
4x = 6 + 2x + 8
4x = 2x + 14
4x - 2x = 14
so your answer is 7,9and 11</span>

3 0

2 years ago

I need help asap:

lisov135 [29]

Answer:

79.4° to the nearest tenth of a degree

Step-by-step explanation:

You are trying to find the angle opposite the side of length 27.

Let the length of that side be c and a and b be the lengths of the other two sides and let C be the measure of the angle you are looking for

Using the law of cosines

$c = \sqrt{a^{2} + b^{2} - 2abcos C}$

$27 = \sqrt{19^{2} + 23^{2} - 2(19)(23)cosC}$

$27^{2} = 19^{2} + 23^{2} - 2(19)(23)cosC$

729 = 361 + 529 - 874cosC

729 = 890 - 874cosC

-161 = -874cosC

-161/-874 = cosC

.1842105.... = cosC

C = arccos .1842105.... = 79.4° to the nearest tenth of a degree

5 0

2 years ago