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4 years ago

Please help me write the equation for the problem below

1 answer:

8 0

Since you want both sides to equal each other, you can set up the following equation:

chess club members = computer club members

500 - 30x = 150 + 20x

x represents the amount of years that have passed. The coefficients for x represent the loss or gain of members per year.

Add 30x to both sides.

500 = 150 + 50x

Subtract 150 from both sides.

350 = 50x

Divide both sides by 50 to solve for x.

x = 7

It will take 7 years for both clubs to have the same amount of members.

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Find a coordinate pair for a point on the graph of 2x + 6y = 2

allochka39001 [22]

Answer:

(0,1/3)

(1,0)

(2,-1/3)

Step-by-step explanation:

3 0

3 years ago

Molly had a $12 gift card to download music. She bought 8 songs that each cost the same amount. Write a variable equation, then

Ghella [55]

Answer:

Molly paid for each song $1.5

Step-by-step explanation:

Let

x ------> amount that Molly paid for each song

we know that

The amount that Molly paid for each song multiplied by 8 is equal to the gift card value

The linear equation that represent this problem is

$8x=12$

Solve for x

Divide by 8 both sides

$x=12/8$

$x=\$1.5$

Molly paid for each song $1.5

4 0

4 years ago

Plz help

frozen [14]

Answer:

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

Step-by-step explanation:

Let p be the number of pies and c be the number of cakes.

Then according to given statement " the store sold 10 baked goods"

$c+p = 10\ \ \ Eqn\ 1$

And

"A cake costs $5 and a pie costs $4"

$5c+4p = 46\ \ \ \ Eqn\ 2$

Using equation 1,

$c=10-p$

Putting this value of c in equation 2:

$5(10-p)+4p = 46\\50-5p+4p = 46\\-p = 46-50\\-p = -4\\p = 4$

Putting p = 4 in equation 1

$c+4 = 10\\c = 10-4\\c =6$

Hence,

a. Required system of equations is:

c+p = 10

5c+4p = 46

b. 6 cakes were sold

7 0

3 years ago

Choose the slope-intercept form of 3x + 2y = 5

lianna [129]

Answer:

Step-by-step explanation:

8 0

3 years ago

Out of the 150 students at a summer camp, 72 signed up for canoeing. there were 23 students who signed up for trekking, and 13 o

True [87]

Answer:

Approximately 45% students signed up for neither canoeing or trekking.

Step-by-step explanation:

First we subtract the number of the students who signed up from the number of the total students to find the number of the students who did not signed up for either.

But there are 13 students who signed up canoeing and also for trekking.

Hence the number of students they signed up for activity is

72 + 23 - 13 = 82

And the number of students they not signed up for any activity is

150 - 82 = 68

so 68 students signed up neither for trekking nor canoeing. The percentage of those students are :

$\frac{68}{150}$ × 100 = 45.3333%

Approximately 45% students signed up for neither canoeing or trekking.

8 0

3 years ago