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Find Slope
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4x + 2y = 2
2y= -4x + 2
y = -4/2 x + 2
y = -2x + 2
Slope = -2
Perpendicular slope = 1/2
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Insert slope into the general equation y = mx + c
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y = 1/2x + c
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Find y-intercept
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y = 1/2x + c
at (5,6)
6 = 1/2 (5) + c
6 = 5/2 + c
c = 6 - 5/2
c = 7/2
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Insert y-intercept into y = 1/2 x + c
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y = 1/2 x + 7/2
2y = x + 7
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Answer: 2y = x + 7
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Divide the whole equation by 2 so it would be y=x+15 or make your graph go by 2 or 5
Dunno dunno...
doesn't have an operation sign
The surface is parameterized by
and the normal to the surface is given by the cross product of the partial derivatives of 
:
It looks like you're given
Then the normal vector is
Now, the point (2, 2, 0) corresponds to u and v such that
and solving gives 
, so the normal vector at the point we care about is
Then the equation of the tangent plane is
