Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
44x/7
Step-by-step explanation:
Radius=r=xcm
Circumference=2πr
➜2πx
➜2×22/7×x
➜44/7×x
➜44x/7
Answer:
-4
Step-by-step explanation:
that is the slope
<span>0.3, 0.1, -0.2, -0.001 are all little to no correlation.
The closer our values get to 1 or -1, the stronger the correlation. Anything below 0.5 is not a strong correlation.</span>