The ratio of the Total surface area
is squared from the scale factor ratio.
So square root the total surface area ratio
1/2
So to get the ratio for volume, it’s cubed
Hence,
1/8
So 1/8 * 3200 = 400
Answer:
If you have a quantity X of a substance, with a decay constant r, then the equation that tells you the amount of substance that you have, at a time t, is:
C(t) = X*e^(-r*t)
Now, we know that:
We have 2000g of substance A, and it has a decay constant of 0.03 (i assume that is in 1/year because the question asks in years)
And we have 3000 grams of substance B, with a decay constant of 0.05.
Then the equations for both of them will be:
Ca = 2000g*e^(-0.03*t)
Cb = 3000g*e^(-0.05*t)
Where t is in years.
We want to find the value of t such that Ca = Cb.
So we need to solve:
2000g*e^(-0.03*t) = 3000g*e^(-0.05*t)
e^(-0.03*t) = (3/2)e^(-0.05*t)
e^(-0.03*t)/e^(-0.05*t) = 3/2
e^(t*(0.05 - 0.03)) = 3/2
e^(t*0.02) = 3/2
Now we can apply Ln(x) to both sides, and get:
Ln(e^(t*0.02)) = Ln(3/2)
t*0.02 = Ln(3/2)
t = Ln(3/2)/0.02 = 20.3
Then after 20.3 years, both substances will have the same mass.
Answer:
7) No
8) Yes
Step-by-step explanation:
Tangent lines are perpendicular to the radius lines at the point of intersection. So we just need to check if these are right triangles.
7) c² = a² + b²
20² = 12² + 14²
400 = 340
No
8) c² = a² + b²
13² = 7.8² + 10.4²
169 = 169
Yes
Answer:
10
Step-by-step explanation:
You do 5C3, which is 5!/((5-3)!3!) -->
5*4*3*2*1/(2*1*3*2*1) =
10
First what you would have to do is distribute the reciprocal to the (d/3 + 2) and the d/3 is canceled out. You are left with h=6/d. When you put the h over 1 in a fraction, it stays the same. Like in trig, you switch the d and the h and you have d/1=6/h.
d=6/h
