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dangina [55]
3 years ago
13

Of Semester Exam Review

Mathematics
1 answer:
ch4aika [34]3 years ago
6 0

Answer:

A ) Near equator

B ) Near the poles

C ) Areas where solar radiations is most direct

D ) Only in the no

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What is the lcm lcm of 8,9 and 10​
vivado [14]

Answer:

360

Step-by-step explanation:

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3 years ago
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If the average of 12 consecutive odd integers is 328, what is the least of these integers
yanalaym [24]
X+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10+x+11+x+12/12
12x+78/12 = 132 times 12 is
12x+78 = 1,548 minus 78
12x = 1,506 divide by 12
x = 125.5 I believe is the answer, sorry if it is wrong



5 0
3 years ago
What mixed number is equivalent to the improper fraction, 46/11? Show your work.
AleksandrR [38]
11 and 2/11 because 46 divided by 11 is 44 plus 2 is 46

7 0
3 years ago
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GUYS PLEASE HELP ME!!
Musya8 [376]
<h3>The surface area of cube is 162.24 square inches</h3>

<em><u>Solution:</u></em>

<em><u>The surface area of cube is given as:</u></em>

Surface\ Area = 6s^2

Where,

"s" is the length of each side of cube

From given,

s = 5.2 inches

Therefore,

Surface\ Area = 6 \times 5.2^2\\\\Surface\ Area =  6 \times 27.04\\\\Surface\ Area = 162.24

Thus the surface area of cube is 162.24 square inches

7 0
3 years ago
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
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