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3 years ago

One random part of Chess is whether the white side or the black side moves first? A. True B. False

Computers and Technology

2 answers:

Korvikt [17]3 years ago

6 0

Yes the answer is A. True

ohaa [14]3 years ago

5 0

The correct answer is B. false.
Determining which color goes first is not random at all - it is a rule in chess that the White player will always start the game first, and will then be followed by the Black player.

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Create a base class named rectangle that contains lenght and width data members.

kumpel [21]

Answer:

class Rectangle:

def __init__(self, length, width):

self.length = length

self.width = width

def area(self):

area = self.length*self.width

return area

class Box (Rectangle):

def __init__(self, length, width, height):

super().__init__(length, width)

self.height = height

def volume(self):

volume = self.length * self.width * self.height

return volume

def area(self):

area = 2*(self.length*self.width) + 2*(self.length*self.height) + 2*(self.width*self.height)

return area

rec_1 = Rectangle(2,4)

box_1 = Box(2,2,6)

print(box_1.length)

print(box_1.area())

print(rec_1.length)

print(rec_1.area())

Explanation:

The programming language used is python.

class Rectangle

The class Rectangle is created with attributes length and width.

The class attributes are initialized using the __init__ constructor.

In the rectangle class, a method/function is declared to return the area of the rectangle.

class Box

This class is a child of rectangle and it inherits all its attributes and methods,

It has an additional attribute of depth and its constructor is used to initialize it.

The class contains a volume function, that returns the volume and an override function 'area()' that displaces the area from the parent class.

Finally, some instances of both classes are created.

4 0

3 years ago

In addition to offering word excel PowerPoint and one note the office home and business edition also offers

algol13

Answer:

Dropbox?

Explanation:

8 0

4 years ago

A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co

tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k ...(1)

probability of 2 hops = k(1-k) ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

= (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

= k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

∞ n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

n-1

= 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet = k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet = $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

6 0

3 years ago

1 : What format would you apply to give an entry the appearance of 12-Mar-2014

Arturiano [62]

Answer:

1. Date 2. It will appear to the right of the selected column.

4 0

3 years ago

In three to four sentences, describe why CEOs (the chief executive officers, that is, the leaders of large companies) make very

mixer [17]

Well, CEOs are on the top of the food chain. It takes a lot of work and ambition to become one, and once they are one, <span>CEOs accept a huge amount of responsibility - that means having to take blame if things go wrong and </span><span>having more tasks to complete such as having to attend numerous meetings, make decisions. They are also on the board of directors.</span>

Assistants do not have to do as much, they likely won't have that much responsibility or experience, their tasks revolve around ensuring meetings are scheduled and performing other ad-hoc duties.

5 0

4 years ago