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Tju [1.3M]
3 years ago
10

One random part of Chess is whether the white side or the black side moves first? A. True B. False

Computers and Technology
2 answers:
Korvikt [17]3 years ago
6 0
Yes the answer is A. True
ohaa [14]3 years ago
5 0
The correct answer is B. false.
Determining which color goes first is not random at all - it is a rule in chess that the White player will always start the game first, and will then be followed by the Black player. 
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This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
Simora [160]

Answer:

// Scanner class is imported to allow program receive user input

import java.util.Scanner;

// class is defined

public class PlayerRoster {

   // main method that begin program execution

  public static void main(String[] args) {

   // Scanner object scan is defined

     Scanner scan = new Scanner(System.in);

   // multi-dimensional array to hold the jersey number and rating

     int[][] players = new int[5][2];

   // boolean flag to keep program alive

     boolean keepAlive = true;

   // the user input is declared as input of type char

     char input;

     

   // for loop that receive 5 player jersey number and ratings

   // it assigns the received input to the already initialized array

     for (int i = 0; i < 5; i++) {

        System.out.println("Enter player " + (i+1) + "'s jersey number: ");

        players[i][0] = scan.nextInt();

        System.out.println("Enter player " + (i+1) + "'s rating: ");

        players[i][1] = scan.nextInt();

        System.out.println();

     }

   // a blank line is printed

     System.out.println();

   // a method is called to display players array

     outputRoster(players, 0);

     

   // while the flag is true

   // display the Menu by calling the outputMenu method

     while (keepAlive) {

        outputMenu();

       // user input is assigned to input

        input = scan.next().charAt(0);

       //  if user input is 'q' then program will quit

        if (input == 'q') {

           keepAlive = false;

           break;

        }

       //  else if input is o, then outputRoaster is called to display players

        else if (input == 'o') {

           outputRoster(players, 0);

        }

       //  else if input is 'u', then user is allowed to edit a player rating

        else if (input == 'u') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           System.out.println("Enter a new rating for the player: ");

           int newRating = scan.nextInt();

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 players[l][1] = newRating;

              }

           }

        }

       //  else if input is 'a', user is allowed to add a new rating

        else if (input == 'a') {

           System.out.println("Enter a rating: ");

           int rating = scan.nextInt();

           outputRoster(players, rating);

        }

        // else if input is 'r', user is allowed to replace a player

        else if (input == 'r') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           boolean exists = true;

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 System.out.println("Enter a new jersey number: ");

                 players[l][0] = scan.nextInt();

                 System.out.println("Enter a rating for the new player: ");

                 players[l][1] = scan.nextInt();

              }

           }

           

        }

     }

     

     return;

  }

 

// this method take two parameters, players and min

// it then returns player with ratings greater than min

  public static void outputRoster(int[][] players, int min) {

     System.out.println(((min>0) ? ("ABOVE " + min) : ("ROSTER")));

     int item = 1;

     for (int[] player : players) {

        if (player[1] > min) {

           System.out.println("Player " + item + " -- Jersey number: " + player[0] + ", Rating: " + player[1]);

        }

        item++;

     }

     System.out.println();

  }

 

// outputMenu method to display the program menu

  public static void outputMenu() {

     System.out.println("MENU");

     System.out.println("u - Update player rating");

     System.out.println("a - Output players above a rating");

     System.out.println("r - Replace player");

     System.out.println("o - Output roster");

     System.out.println("q - Quit\n");

     System.out.println("Choose an option: ");  

  }

}

Explanation:

The program is written in Java and it is well commented.                                          

5 0
3 years ago
Using a conversation voice is part of:
MaRussiya [10]
Need more information
4 0
3 years ago
Your company has a team of remote workers that need to use Windows-based software to develop company applications, but your team
timofeeve [1]

Operating systems are the software that supports the basic functioning of the computer. Windows Virtual Desktop is an Azure compute service that will help solve the problem.

<h3>What is Windows Virtual Desktop?</h3>

Windows Virtual Desktop is an app virtualization service of Azure that operates on the cloud platform. It includes standard operating procedures that can be used by users with multiple OS.

Azure's Virtual Desktop supports different versions of window OS. This type of system is majorly used in remote work demands and specialized workloads.

Therefore, Windows Virtual Desktop is an Azure compute service.

Learn more about Azures service here:

brainly.com/question/13144160

#SPJ1

5 0
2 years ago
US-CERT is a set of moderated mailing lists full of detailed, full-disclosure discussions and announcements about computer secur
n200080 [17]

Answer:

False

Explanation:

BugTraq is a high volume, full disclosure mailing list for the detailed discussion and announcement of computer security vulnerabilities, not US-CERT

3 0
3 years ago
The enhanced for statement allows you to iterate through the elements of an array or a collection without using a counter. Give
lesya [120]

Answer:

Check the explanation

Explanation:

public class EnhancedForExample {

   public static void main(String[] args) {

       int[] arr = {4, 2, 9, 1, 5, 7};

       for(int num : arr) {

           System.out.println(num);

       }

   }

}

Kindly check the attached image below for the code output.

7 0
3 years ago
Read 2 more answers
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