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Semenov [28]
4 years ago
9

This is the amount paid or charged for something.

Mathematics
2 answers:
guajiro [1.7K]4 years ago
4 0

Answer:

the cost or price of something

Step-by-step explanation:

Firdavs [7]4 years ago
4 0

Answer:

cost

Step-by-step explanation:

What is the amount paid or charged for something?

If you charge someone, you ask them to pay an amount of money for something that you have sold to them or done for them. The federal funds rate is the interest rate that banks charge one another for short-term loans.

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A rectangular field is 75 yards wide and 105 yards long
nika2105 [10]

Answer:

width = 72 yards

length = 108 yards

Step-by-step explanation:

Given:

  • Width = 75 yards
  • Length = 105 yards

<u>Area of the field</u> with the given values:

\begin{aligned}\textsf{Area of a rectangle}&=\sf width \times length\\& = \sf 75 \times 105\\& = \sf 7875\:\: yd^2\end{aligned}

To maintain the <u>same perimeter</u>, but <u>change the area</u>, either:

  • decrease the width and increase the length by the same amount, or
  • increase the width and decrease the length by the same amount.

In geometry, length pertains to the <u>longest side</u> of the rectangle while width is the <u>shorter side</u>.  Therefore, we should choose:

  • decrease the <u>width</u> and increase the <u>length</u> by the <u>same amount</u>.

<u>Define the variables</u>:

  • Let x = the amount by which to decrease/increase the width and length.

Therefore:

\implies \sf width \times length < 7875\:\:yd^2

\implies (75-x)(105+x) < 7875

Solve the inequality:

\begin{aligned}(75-x)(105+x) & < 7875\\7875-30x-x^2 & < 7875\\-x^2-30x & < 0\\-x(x+30) & < 0\\x(x+30) & > 0\\\implies x & > 0 \:\: \textsf{ or }\:\:x < - 30\end{aligned}

Therefore, as distance is positive only and the maximum width is 75 yd (since we are subtracting from the original width):

\begin{cases}\textsf{width} = 75 - x\\\textsf{length} = 105 + x\end{cases}

\textsf{where } 0 < x < 75

Therefore, to find the width and length of another rectangular field that has the same perimeter but a smaller area than the first field, simply substitute a value of x from the restricted interval into the found expressions for width and length:

<u>Example 1</u>:

  • Let x = 3

⇒ Width = 75 - 3 = 72 yd

⇒ Length = 105 + 3 = 108 yd

⇒ Perimeter = 2(72 + 108) = 360 yd

⇒ Area = 72 × 108 = 7776 yd²

<u>Example 2</u>:

  • Let x = 74

⇒ Width = 75 - 74 = 1 yd

⇒ Length = 105 + 74 = 179 yd

⇒ Perimeter = 2(1 + 179) = 360 yd

⇒ Area = 1 × 179 = 179 yd²

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2 years ago
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HELP PLEASE!! 20 POINTS
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The answer is c. As you can see from the graph, -2 is the smallest y value and 4 is the biggest. Therefore, the range is -2
7 0
4 years ago
If f(x)=3x+10x and g(x)=2x-4 find(f+g)(x)
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3x+10x + 2x-4=
15x -4
3 0
4 years ago
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How to solve this problem.
andreyandreev [35.5K]
Notice the picture below

now, if the arc "x" is 48°, and the arc across the circle is also 48°, then those chords are congruent, notice the chords in red

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Integrate cos(2theta)d(theta) from 0 to pi/5
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\int\limits^ \frac{ \pi }{4}  _0 {cos2t} \, dt  =  \frac{sin2t}{2} I\limits^ \frac{ \pi }{4} _0   = \\ = \frac{sin( \pi/2) }{2}- \frac{sin (0)}{2}=  \frac{1}{2}
Answer: 1/2
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3 years ago
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