Given:
Temperature in the morning = 6°F.
By the late afternoon, the temperature had dropped 9°F.
To find:
The temperature by the late afternoon.
Solution:
Temperature by the late afternoon = Morning temperature - Dropped temperature
Using the given values and the above formula, we get
Temperature by the late afternoon = 6°F - 9°F
Temperature by the late afternoon = -3°F
Therefore, the temperature by the late afternoon is -3°F.
The first part of the question is not needed
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
nearest tenth=12.1
473,000 u round up to the next thousand
After converting to common denominator:
8/18, 7/18, 6/18, 5/18
so the next fraction is 4/18, but if you have to simplify it’s 2/9
The formula of a midpoint SR:
We have
S(4, 1) and M(7, -5)
Substitute:
<h3>Answer: R(10, -11)</h3>
