All categories

3 years ago

DUE: 10-31-2019

Mathematics

1 answer:

Mamont248 [21]3 years ago

5 0

Answer:

Here's what I get

Step-by-step explanation:

I plotted the triangles in the diagram below.

Part A

The scale factor for dilation is ½, because every coordinate has been halved.

P (8, 0) ⟶ P' (4, 0)

Q (6, 2) ⟶ Q' (3, 1)

R (-2, -4) ⟶ R' (-1, -2)

Part B

When you reflect a point (x, y) about the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

P' (4,0) ⟶ P" (-4,0)

Q' (3,-1) ⟶ Q" (-3,-1)

R' (-1,-2) ⟶ R" (1,-2)

∆P"Q"R" has coordinates P" (-4,0), Q" (-3,-1), R"(1,-2).

Part C

∆PQR and ∆ P"Q"R" are not congruent, because corresponding sides are not equal.

You might be interested in

A local businessman bought a square plot of land. The sides of the lot measure 32 feet on each side. He decides to split the lot

Semmy [17]

Answer:

The sides of a right triangle all right triangles fall under the identity a^2 + b^2 = c^2. Thus, if you draw the picture, you know that both a and b will be 32 feet. You plug 32 in, and get 32^2 + 32^2 =2048. The square root of 2048=45.25 ft. Thus, the diagonal will be 45.25 feet.

Step-by-step explanation:

this is the correct formula to figure out equal sided right triangle

5 0

3 years ago

Solve in order of operation<br> Thanks

Greeley [361]

Answer:

b=40

c=12

Step-by-step explanation:

b) 3+7(8-6)2

10(2)2

20^2 =40

C) 4+(−3) 2 −2÷( 6/3)

4+9− 2/6/3

13-2/6/3

13-2x3/6

13-6/6

13-1

c=12

7 0

3 years ago

Read 2 more answers

PLS I NEED HELP FASTTT

seropon [69]

Answer:

3rd option

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If TU =UV and T has a coordinate of -17 and U has coordinate 2, what is the coordinate of V?

Alex787 [66]

Step-by-step explanation:

this is one-dimensional ? everything just on one number line ?

TU = 2 - -17 = 2 + 17 = 19

TU is 19 units long (17 units on the negative side, and 2 units on the positive side of the number line).

therefore, to make TU = UV a true statement, UV has also to be 19 units long.

as U = 2,

V = U + UV = 2 + 19 = 21

5 0

1 year ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Therefore, the zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

4 0

3 years ago

Read 2 more answers