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2 years ago

How much money is 15% of $14.90 SHOW YOUR WORK

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

4 0

Answer:

The final price will be $12.67

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 14.9 × 15/100

Discount = 14.9 x 0.15

You save = $2.24

Final Price = Original Price - Discount

Final Price = 14.9 - 2.235

Final Price = $12.67

hope this helps and is right. p.s. i really need brainliest :)

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The value of the fraction 3c+2/4 one less than the value of the fraction 5c-1/3.

Viefleur [7K]

Answer:

7/8 > 5/6

Step-by-step explanation:

A) 7/8

We can compare this as follows.

Lets say both are equal.

Cross multiplying these we get 40=42

We get 40<42. In fraction we get

In case if you want to convert this to decimal, we get;

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B) 4/5

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C) 3/4

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D) 2/3

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Step-by-step explanation:

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3 years ago

The actual length of side y is 22 cm. Use the scale drawing to find the actual length of side x. A) 15.2 cm B) 17.1 cm C) 18.0 c

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3 years ago

Read 2 more answers

A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r

Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

$P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5$

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, $n(S)=6$

Now, probability of rolling a 3 is given as:

$P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}$

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

$P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083$

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0

3 years ago