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patriot [66]
3 years ago
15

Finding whole number equal to fraction 8/1

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
5 0

Answer: 8

Step-by-step explanation: 8 divided by 1 is 8

Vera_Pavlovna [14]3 years ago
3 0
The answer to this is 8
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Alex earn 12% Commission on any of her monthly sales over $5,000 for sales for May were $6,750 how much commission did Alex earn
Naddika [18.5K]

Answer:

you're question is complicated

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
4. According to statistics reported on IN-CORP a surprising number of motor vehicles are not covered by insurance. Sample result
son4ous [18]

Answer:

a) 0.23

b) The 95% confidence interval for the population proportion is (0.1717, 0.2883).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Point estimate

The point estimate is:

\pi = \frac{46}{200} = 0.23

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 - 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.1717

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.23 + 1.96\sqrt{\frac{0.23*0.77}{200}} = 0.2883

The 95% confidence interval for the population proportion is (0.1717, 0.2883).

5 0
3 years ago
The cost of printing books C varies partly as the amount A charged by the printer
lawyer [7]

The equation connecting C,A and n is  C = 25A - \frac{49990000}{n}

<h3>What is variation?</h3>

Variation is a mathematical term used to show how a quantity behaves when one quantity increases or decreases.

Analysis:

C = AK + M/n

where K and M are constants

when n = 1000, A = 5000, C = 75010

75010 = 5000K + M/1000-----------1

50004 = 10000k + M/200-------------2

solving simultaneously,  K = 25, M = -49990000

C = 25A - 49990000/n

In conclusion, the equation connecting C,A and n is C = 25A - 49990000/n

Learn more about variation: brainly.com/question/6499629

#SPJ1

6 0
2 years ago
a In each of the following, find the zeros and indicate the multiplicity of each zero. What is the degree of the polynomial? f(x
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Answer:

ffhhvfhhhhhhhhhhhhhhhhhhhhhhhhhh

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2 years ago
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